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Nat2105 [25]
3 years ago
8

What is the gravitational potential energy of a 1.3 kg book that is 473

Physics
1 answer:
Dmitrij [34]3 years ago
7 0

Answer:

3047710272

Explanation:

556ijnhvcdse4456679908

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Assume that a resistor is connected between the 150 V terminal and the common terminal. The voltmeter is then connected to an un
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Answer: 316.8V

Explanation:

given data:

metre moving current = 0.96mA

meters voltage = 288V

or  0.96*300V = 288V

<u><em>Solution:</em></u>

<u><em /></u>v1 = (0.96mA*150)<u><em /></u>

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i1 = \frac{144v}{750}

= 0.192mA

i2 = imovement + i1

i2= 0.96mA+0.192mA

= 1.152mA

Vmeasured = 144V+(150)(1.152mA)

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the unknown voltage is 316.8V

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Determine the density of a rectangular piece of concrete that measures 3.7 cm by 2.1 cm by 5.8 cm and has a mass of 43.8 grams.
Novay_Z [31]
It is customary to work in SI units.

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V = 3.7*2.1*5.8 cm³ = 45.066 cm³ = 45.066 x 10 ⁻⁶ m³

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