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Arturiano [62]
2 years ago
8

0v0 h e l p? 3r/4=1/8 (solve for r)

Mathematics
1 answer:
agasfer [191]2 years ago
3 0

Answer:

r = 1/6

Step-by-step explanation:

\dfrac{3}{4}r=\dfrac{1}{8}\\\\\\

Multiply both sides by 4

4*\dfrac{3}{4}r=4*\dfrac{1}{8}\\\\3r = \dfrac{1}{2}

Divide both sides by 3

\dfrac{3}{3}r=\dfrac{1}{2*3}\\\\r = \dfrac{1}{6}

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Match each equation to its solution -3x+7=28
LuckyWell [14K]

Answer:

-7

Step-by-step explanation:

5 0
3 years ago
How can you tell if the expression 7x-4 and 6x-4-x are equivalent
olga_2 [115]

Answer:

see below

Step-by-step explanation:

7x-4          6x-4-x

Combine like terms on the second expression

7x -4          6x -x -4

                 5x -4

These are not equivalent  expressions

7x -4  does not equal 5x-4

8 0
3 years ago
Which of the binomials below is a factor of this trinomial? -3x^2-21x+24 x-4 x+1 x+4 x-1
OleMash [197]

Answer:

-3x^2-21x+24

Step-by-step explanation:

Kindly separate the answer choices:  (x - 4), (x + 1), (x + 4) , (x - 1).  The trinomial is thus -3x^2-21x+24, which can be factored as follows:  -3(x^2 + 7x - 8)

Then we have -3x^2-21x+24 = -3(x^2 + 7x - 8), which factors further into:

-3(x + 8)(x -1)  and so we conclude that the only binomial that is a factor of

-3x^2-21x+24 is (x - 1).

5 0
3 years ago
Find the length of the missing side for a right triangle with the given sides. Side c is the hypotenuse. Sides a and b are the l
valkas [14]

Answer:

You can calucate b by using pythagorean theorem:

a² + b² = c²

21² + b² = 29²

        b² = 841 - 441 = 400

        b  = √400 = 20 (m)

5 0
3 years ago
Can anyone help me with this exercise?
Nookie1986 [14]

Answer:

View Image

Step-by-step explanation:

Your first step is to solve for y on both equations.

You solve treat the inequality sign just like an equal sign and solve for it.

Graph your equations as if the inequality sign isn't there.

Use dotted lines for < and >

Use solid lines for ≤ and ≥

If it's less than, < or ≤, then shade underneath the line.

If it's greater than, > or ≥, then shade above the line.

3 0
3 years ago
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