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3 years ago

True or False One of the objections to the solar nebula theory is the angular momentum problem.

Physics

1 answer:

KengaRu [80]3 years ago

5 0

Answer:

False, the angular momentum problem is not one of the objections to the solar nebular theory.

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If you were to measure the width of your lab manual with a meter stick, and then the length (roughly 50% longer), by what fracti

Leona [35]

Answer:

Explanation:

a ) Let breadth be L , then length will be 1.5 L

Since it is a meter scale , the least count is 1 m.m. So

maximum possible error in a measurement is 1 mm.

In both the measurement of length and breadth , absolute

uncertainty will be 1mm.

Hence there is no difference in absolute uncertainty of their measurement.

b ) percent uncertainty in the measurement of length

$\frac{1 mm}{1.5L\times1000} \times100$

= 1 / 15L%

percent uncertainty in the measurement of breadth

$\frac{1 mm}{L\times1000} \times100$

1 / 10L%

In breadth it will be higher by

( 1/10L - 1/15L)/ 1/10L

= 1/3

c ) Uncertainty in the measurement of R= 1 %

Area A = π R²

ΔA/A X100 = 2 X ΔR/R X 100

Percentage uncertainty in A = 2 X percentage uncertainty in R

= 2 X 1

=2 %

Therefore percentage accuracy in the calculation of area

= 2 %.

7 0

3 years ago

True or false

Alex Ar [27]

Your answer is true to this question i hope this is correct

8 0

3 years ago

Jo wants to find out about floating and sinking. She puts a rubber duck and a bar of soap in a

maks197457 [2]

Answer:

the soap sinks because it is more dense than the duck.

7 0

3 years ago

A 1.2 m long wave travels 11.2 m to a wall and back again in 4.0 s. What is

algol [13]

Answer:

f = 4.67 Hz

Explanation:

We can approximate the wave as a traveling wave, therefore the speed of the wave is constant

v = d / t

the total distance remember, in going to the wall and back is

d = 2 11.2 = 22.4 me

we substitute

v = 22.4 / 4.0

v = 5.6 m / s

now we can use the relationship between the speed of the wave, its wavelength and u frequency

v =λ f

f = v /λ

f = 5.6 / 1.2

f = 4.67 Hz

3 0

3 years ago

Three deer, A, B, and C, are grazing in a field. Deer B is located 62m from deer A at an angle of 51° north of West. Deer C is l

Anna71 [15]

Set deer A's position to be the origin. Let $c$ be the distance from deer A to deer C. We're given that deer B is 95 m away from deer C, which means the length of the vector $B-C$ is 95 (or $C-B$ ). Then

$|B-C|^2=(B-C)\cdot(B-C)=B\cdot B-2B\cdot C+C\cdot C=|B|^2-2B\cdot C+|C|^2$

$|B-C|^2=|B|^2-2|B||C|\cos(180-77-51)^\circ+c^2$

$95^2=62^2-2(62)(c)\cos52^\circ+c^2$

$c^2-124\cos52^\circ c-5181=0\implies c=120\,\mathrm m$

8 0

4 years ago