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kkurt [141]
4 years ago
9

1/3 + (-7/4) = write your answer in an fraction in simplest form

Mathematics
1 answer:
pentagon [3]4 years ago
8 0

Answer:

17/12

Step-by-step explanation:

i hope this is right

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Find m2ABC<br> (3x + 8)<br><br> (5x - 40)
Virty [35]

Answer:

Step-by-step explanation:

(3x + 8) =(5x - 40)

Remove the brackets and replace 3x with -40 and -40 with 3x.

40 + 8 =5x - 3x  (Remember that when you replace, the signs change from negative to positive and vise versa)

Solve for x. x= -24

Replace x with its value.

3(-24)+ 8= -64

5(-24) - 40= -160

7 0
3 years ago
Question 21 [t-interval] a random sample of size 18 is drawn from a population that is normally distributed. the sample mean is
iren2701 [21]

Answer:

Option a. [52.78,64.22]

Step-by-step explanation:

We are given that a random sample of size 18 is drawn from a population that is normally distributed.

Sample mean is 58.5, and the sample standard deviation is found to be 11.5 i.e., X bar = 58.5  and  s = 11.5

The pivotal quantity for calculating 95% confidence interval is;

               \frac{Xbar - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

So, 95% confidence interval about population mean is given by;

P(-2.110 < t_1_7 < 2.110) = 0.95

P(-2.110 < \frac{Xbar - \mu}{\frac{s}{\sqrt{n} } } < 2.110) = 0.95

P(-2.110 * \frac{s}{\sqrt{n} } < {Xbar - \mu} < 2.110 * \frac{s}{\sqrt{n} } ) = 0.95

P(X bar - 2.110 * \frac{s}{\sqrt{n} } < \mu < X bar + 2.110 * \frac{s}{\sqrt{n} } ) = 0.95

95% confidence interval about \mu = [ X bar - 2.110 * \frac{s}{\sqrt{n} } , X bar + 2.110 * \frac{s}{\sqrt{n} } ]

                                                   = [ 58.5 - 2.110 * \frac{11.5}{\sqrt{18} } , 58.5 + 2.110 * \frac{11.5}{\sqrt{18} } ]

                                                   = [ 52.78 , 64.22 ]

Therefore, 95% confidence interval about population mean is [52.78 , 64.22].

7 0
3 years ago
- The product of a number and 18<br> decreased by 1 is 37
dimulka [17.4K]

Answer: 2

Step-by-step explanation:

3 0
3 years ago
Maxwell Fischer, beekeeper. Annual group insurance cost $5.768. Employer pays 71
kramer
The Fischer gets 21$ by the end the empl
7 0
3 years ago
if (x + p) is a factor of both x^2 + 16x + 64 and 4x^2 + 37x + k, where p and k are nonzero integer constraints, what could be t
Murljashka [212]

Step-by-step explanation:

x² + 16x + 64 = (x + 8)². Hence p = 8.

Since (x + 8) is a factor of 4x² + 37x + k,

4(-8)² + 37(-8) + k = 0. (by Factor Theorem)

=> 256 - 296 + k = 0

=> k - 40 = 0

=> k = 40.

The value of k is 40.

6 0
3 years ago
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