Answer:
7g
Explanation:
Given parameters:
Mass of sodium = 3g
Mass of chlorine = 4g
Unknown:
Total mass of sodium chloride = ?
Solution:
This problem entails the direct application of the law of conservation of mass. According to this law, it states that "matter is neither created nor destroyed in the course of a chemical reaction".
So, when sodium and chlorine combines to form sodium chloride, to are expect to produce substance with a mass which adds up to the sum of the reactants;
Mass of sodium chloride = mass of sodium + mass of chlorine
= 3g + 4g
= 7g
Answer:
When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K
Explanation:
Step 1: Data given
A sample of sulfur hexafluoride gas occupies a volume of 5.10 L
Temperature = 198 °C = 471 K
The volume will be reduced to 2.50 L
Step 2 Calculate the new temperature via Charles' law
V1/T2 = V2/T2
⇒with V1 = the initial volume of sulfur hexafluoride gas = 5.10 L
⇒with T1 = the initial temperature of sulfur hexafluoride gas = 471 K
⇒with V2 = the reduced volume of the gas = 2.50 L
⇒with T2 = the new temperature = TO BE DETERMINED
5.10 L / 471 K = 2.50 L / T2
T2 = 2.50 L / (5.10 L / 471 K)
T2 = 230.9 K = -42.1
When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K
The given question is incomplete. The complete question is :
Gaseous butane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If 1.31g of water is produced from the reaction of 4.65g of butane and 10.8g of oxygen gas, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.
Answer: 28.0 %
Explanation:
To calculate the moles :
According to stoichiometry :
13 moles of require 2 moles of butane
Thus 0.34 moles of will require= of butane
Thus is the limiting reagent as it limits the formation of product and butane is the excess reagent.
As 13 moles of give = 10 moles of
Thus 0.34 moles of give = of
Mass of
The percent yield of water is 28.0 %