Answer:
The answer to your question is the letter C) 5648 kJ/mol
Explanation:
Data
C₁₂H₂₂O₁₁ + 12 O₂ ⇒ 12 CO₂ + 11 H₂O
H° C₁₂H₂₂O₁₁ = -2221.8 kJ/mol
H° O₂ = 0 kJ / mol
H° CO₂ = -393.5 kJ/mol
H° H₂O = -285.8 kJ/mol
Formula
ΔH° = ∑H° products - ∑H° reactants
Substitution
ΔH° = 12(-393.5) + 11(-285.8) - (-2221.8) - (0)
ΔH° = -4722 - 3143.8 + 2221.8
Result
ΔH° = -5644 kJ/mol
The stomach produces digestive enzymes to help break down food and etc. also the pancreas and small intestines
Answer is: 22,4 l of nitrogen.
Chemical reaction: 3H₂ + N₂ ⇄ 2NH₃.
V(NH₃) = 44,8 l = 44,8 dm³.
V(N₂) = ?
n(NH₃) = V(NH₃) ÷ Vm
n(NH₃) = 44,8 dm³ ÷ 22,4 dm³/mol
n(NH₃) = 2 mol.
from reaction: n(N₂) : n(NH₃) = 1 : 2
n(N₂) : 2 mol = 1 : 2
n(N₂) = 1 mol.
V(N₂) = n(N₂) · Vm
V(N₂) = 1 mol · 22,4 dm³/mol = 22,4 dm³.
Vm - molar volume
Answer: Option (a) is the correct answer.
Explanation:
Ionic bond is formed by the transfer of electrons.
Metals contain more number of electrons, so in order to attain stability they easily lose excess of electrons. This results in the formation of positive ions.
Thus, metals form ionic bonds.
Hence, we can conclude that metals lose their valence electrons and form positive ions.
Answer:
The answer is Kr (Krypton).
This is because krypton has an electronic configuration of:
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6
Taking note of the sequence of electronic configuration:
1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s
It can be seen that Kyrpton's electronic configuration finishes just before the 5s subshell. Therefore, the noble gas notation for an element with valence electrons in the 5s subshell can use [Kr] as a shortcut to denote its electronic configuration. For example:
If an element has 1 valence electron in the 5s subshell, the noble gas notation will be:
[Kr] 5s1
Explanation:
