Question

How many molecules of O2 are required to react with 3.00 moles P4? P4+5O2⟶2P2O5

Answer 1

Answer:

1400

Explanation:

Answer 2

Answer:

$9,03.10x^{24}$ molecules of $O_2$

Explanation:

We have the following balanced equation

$P_4+5O_2 \longrightarrow 2P_2O_5$

According to the stoichiometric coefficients of the reagents for each mole of $P_4$, 5 moles of $O_2$ are needed,

We apply a simple three rule to find out how many moles of O2 are required for 3 moles of P4 to react

$1 mol P_4 \longrightarrow 5 mol O_2\\3 mol P_4\longrightarrow x \\x=\frac{(3molP_4)(5molO_2)}{1molP_4} \\x= 15 molO_2$

Now we know that we need 15 moles of $O_2$ so that 3 moles of $P_4$ reactions

Remember that 1 mole (of any element or substance) is equal $6,02.10^{23}$ molecules

To find out how many molecules of O2 are required we apply a simple rule of three

$1 mol O_2 \longrightarrow6,02.10^{23}molecules \\15 molO_2 \longrightarrow x \\x=\frac{(15molO_2)(6,02.10^{23}molecules)}{1molO_2} \\x=9,03.10^{24} molecules$

To react 3 moles of$P_4$, $9,03.10^{24}$ molecules of $O_2$ are required