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3 years ago

Could we create a vacuum inside a balloon in order to make it float. Why or why not

Physics

2 answers:

maxonik [38]3 years ago

5 0

Answer:

it will pop

Explanation:

yuradex [85]3 years ago

4 0

No becuase it will pop right away the balloon isn’t strong enough

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Can you die if you bust a hemorrhoid?

SVEN [57.7K]

I think that you can die

8 0

3 years ago

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It is found that the most probable speed of molecules in a gas at equilibrium temperature

kaheart [24]

Answer:

$\frac{T_2}{T_1} = 1$

Explanation:

The root mean square velocity of the gas at an equilibrium temperature is given by the following formula:

$v = \sqrt{\frac{3RT}{M} }$

where,

v = root mean square velocity of molecules:

R = Universal Gas Constant

T = Equilibrium Temperature

M = Molecular Mass of the Gas

Therefore,

For T = T₁ :

$v = \sqrt{\frac{3RT_1}{M} }$

For T = T₂ :

$v = \sqrt{\frac{3RT_2}{M} }$

Since both speeds are given to be equal. Therefore, comparing both equations, we get:

$\sqrt{\frac{3RT_1}{M} }=\sqrt{\frac{3RT_2}{M} }\\\\\frac{T_2}{T_1} = 1$

8 0

3 years ago

When a deck of cards slips out of your hands and falls to the ground, gravity<br> does work on it

motikmotik

Answer:

yes

Explanation:

3 0

3 years ago

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Bob is moving at 0.967c with respect to Alice. At the exact instant he passes Alice, she fires a very short laser pulse in the s

yulyashka [42]

Explanation:

Speed of Bob, v = 0.967 c

At the exact instant he passes Alice, she fires a very short laser pulse in the same direction Bob is moving.

(a) We need to find the distance measured by Alice between Bob and the laser pulse. It is given by :

$d=ct-vt$

$d=t(c-v)$

$d=5.59\times (c-0.967c)$

$d=5.53\times 10^7\ meters$

(b) Distance measured by Bob between himself and the laser pulse is given by :

$d_B=ct$

$d_B=3\times 10^8\times 5.59$

$d_B=6.67\times 10^9\ meters$

Hence, this is the required solution.

8 0

3 years ago

The circuit shown in the figure (Figure 1) uses a neon-filled tube. This neon lamp has a threshold voltage V0 for conduction, be

Svetllana [295]

Part 1)

Answer:

Explanation:

As we know by equation of charging of the capacitor we will have

$V = E(1 - e^{-t/RC})$

so we will have

$87 = 105(1 - e^{-t/RC})$

here we know that

$R = 3.00 \times 10^6 ohm$

$C = 0.250 \mu F$

so we have

$t = 1.32 s$

Part b)

Answer:

The time will increase.

Explanation:

As we know that on increasing the value of the resistance the the product of the resistance and capacitance will increase so the time will increase to get the above voltage.

Part c)

Answer:

The capacitor discharges through a very low resistance (the lamp filled with ionized gas), and so the discharge time constant is very short. Thus the flash is very brief.

Explanation:

Since the lamp resistance is very small so the energy across the lamp will totally lost in very short interval of time

Part d)

Answer:

Once the lamp has flashed, the stored energy in the capacitor is gone, and there is no source of charge to maintain the lamp current. The lamp "goes out", the lamp resistance increases, and the capacitor starts to recharge. It charges again and the process will repeat.

Explanation:

Since we know that the battery is connected to the given system so after whole energy of capacitor is flashed out it is again charged by the battery and the process will continue

3 0

4 years ago