Answer:
third option mechanical weathering
Step-by-step explanation:
in mechanical weathering it breaks the rock into smaller pieces . these smaller pieces are just like the bigger rock , just smaller .
Answer:
Apple
Orange
Step-by-step explanation:
Apple has the greater median with a median value of 150 which is more than that of orange at 130
The sample with the greater variability is the orange sample as the interquartile range value of 11 is greater Than 8 for Apple.
Yes it is possible, because of the greater variation on weight shown by the sample of oranges, then it could be possible.
Answer:
0.2915
Step-by-step explanation:
Let W represent water and D represent Dying probability
W = water
D = die
->If with water, it will die with probability 0.4
P(W & D) = 0.82 x 0.4 = 0.328
->Without water the plant will die with probability 0.75
P(W ' & D) = 0.18 x 0.75 = 0.135
Taking sum of the above values with water and without water.
P(D) = P(W & D) + P(W ' & D) = 0.4643
P(W ' | D) = P(W ' & D) / P(D)
= 0.135 /0.463
= 0.2915 ≈ 29.15%
Thus, the probability the neighbor forgot to water is 0.2915
Answer:
14.4 would be the answer hope this is helpful
Step-by-step explanation:
14.4/30= 48%
The value of x is 23.
Simply find the scale factor or what was used to dilate △MAH to produce △WCF.
Use the equation copy over the original,

Reduce,

So our scale factor is ¼ or 0.25
So if we use it and multiply the corresponding side of the missing side with the original we get,

Therefore 23 is our missing side! !
~~
I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey