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miskamm [114]
2 years ago
6

What is fluid called that is inside plants vascular system

Biology
2 answers:
Vladimir79 [104]2 years ago
3 0

Answer:

xylem

Explanation:

xylem

The vascular system of plants has two transport tissues, called xylem and phloem. Xylem transports water and minerals, while phloem transports a variety of dissolved substances, including sugars and amino acids, throughout the plant.

tankabanditka [31]2 years ago
3 0

Answer:

Xylem

Explanation:

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What would the growth equation look like for sessile populations (Sessile populations can’t move, like a barnacle)?
pantera1 [17]

Answer:

births - deaths = growth

Explanation:

(births - deaths) + (immigrants - emmigrants) is what you would normally use to calculate the growth of a population, but because they can't move, you can cut out the immigrant and emmigrant part of the equation.

5 0
3 years ago
The abbreviation for a sudden deficient supply of blood to the brain lasting a short time is
LUCKY_DIMON [66]
The answer would be TIA

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2 years ago
Which statement is true about passive transport?
cestrela7 [59]

Answer:

I think its chemical energy is not required because passive transport doesn't need energy at all

7 0
3 years ago
Why do embryologist study embryos?
ch4aika [34]
Embryologist study embryos because Embryology is central to evolutionary developmental biology ("evo-devo"), which studies the genetic control of the development process (e.g. morphogens), its link to cell signalling, its roles in certain diseases and mutations, and its links to stem cell research.
4 0
3 years ago
A sand storage tank used by the highway department for winter storms is leaking. As the sand leaks out, it forms a conical pile.
harina [27]

Answer:

Rate of change of volume of the pile  = 54\pi

Explanation:

Given -

Rate of increase of the base of the pile = 0.75 inches per minute

Height of the pile = 2 * the radius of the base

Let "h"  be the height of the pile and "r" be the radius of the base.

Then h = 2* r

Radius "r" = 6 inches

Rate of change of radius i.e

\frac{dr}{dt} = 0.75

Volume of conical pile

\frac{\pi }{3} * r^2 * h\\= \frac{\pi }{3} * r^2 * 2 * r\\= \frac{\pi }{3} *2* r^3

Change in volume of conical pile

\frac{dV}{dt} =  \frac{dr}{dt}  * \frac{6* \pi * r^2 }{3}

Substituting the value of rate of change of radius, we get -

\frac{dV}{dt}  = 2 * \pi * (6^2) * (0.75)\\\frac{dV}{dt}  = 54 \pi

Rate of change of volume of the pile  = 54\pi

8 0
3 years ago
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