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3 years ago

Which factor contributes the most to the rates of diffusion and effusion between two gases in a mixture?

Chemistry

1 answer:

sergejj [24]3 years ago

5 0

Answer:

b)The molar mass of the particles.

Explanation:

The rate of effusion of a gas is inversely proportional to the square root of its molar mass (Graham's law), a relationship that closely approximates the rate of diffusion. As a result, light gases tend to diffuse and effuse much more rapidly than heavier gases.

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Although objects can go through physical and changes, the amount of matter in those objects remains the same. This is known as t

Liula [17]

The question above is incomplete, the options attached tot he question are given below:
A. A structure made of building blocks.

The blocks of the same structure bundled in a pile.

B. A snowman.

The melted remains of the same snowman.

C. A lump of clay.

The same lump broken into three pieces.

D. 1 cup of water and one gram of salt, separated.

The same cup of water with one gram of salt mixed in.

E. One apple.

The same apple cut into slices.

ANSWER:

The correct options are these:

B. A Snowman and the melted remain of the same snowman.

C. Lump of clay and the same clay broken into three pieces.

E. One apple and the same apple cut into slices.

For all the three answers listed above, the mass of the pairs will remain the same because nothing has been taken out of them and nothing is added to them, they were just changed from one form to another. The other options are wrong because, something got added to the original material.

4 0

3 years ago

In the substance, iron (II) sulfate, which element is in the greatest percentage by mass?

nekit [7.7K]

Oxygen (O) = 42,129%

7 0

3 years ago

Heat by radiation will most likely be transferred through ___

iris [78.8K]

Answer:

Explanation:

I think it is d sorry if wrong hoped I helped

7 0

4 years ago

If you had excess chlorine, how many moles of aluminum chloride could be produced from 28.0 g of aluminum?

MaRussiya [10]

Answer:

1.04 moles of AlCl₃

Explanation:

Balanced Equation: 2Al°(s) + 3Cl₂(g) => 2AlCl₃(s)

Approach => convert given data (28 g Al°) to moles. The number of moles AlCl₃ would equal the number of moles aluminum because coefficients for Aluminum and Aluminum Chloride are equal.

moles Al° = (28g)/(27g/mole ) = 1.04 mole Al°

From balanced equation moles AlCl₃ produced equals moles of Al° produced = 1.04 mole AlCl₃ because coefficients of Al° & AlCl₃.

5 0

4 years ago

A mixture of methane and krypton gases is maintained in a 8.99 L flask at a pressure of 1.68 atm and a temperature of 46 °C. If

sweet-ann [11.9K]

Answer:

22.81 g

Explanation:

Given that:

Pressure = 1.68 atm

Temperature = 46 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (46 + 273.15) K = 319.15 K

Volume = 8.99 L

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1.68 atm × 8.99 L = n × 0.0821 L.atm/K.mol × 319.15 K

⇒n = 0.5764 moles

Given that :

Amount of methane = 4.88 g

Molar mass = 16.04 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{4.88\ g}{16.04\ g/mol}$

$Moles= 0.3042\ mol$

Moles of Krypton = Total moles - Moles of methane = 0.5764 - 0.3042 moles = 0.2722 moles

Also, Molar mass of krypton = 83.798 g/mol

So,

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.2722\ moles=\frac{Mass}{83.798\ g/mol}$

Mass of krypton = 22.81 g

6 0

3 years ago