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Ymorist [56]
3 years ago
12

Although objects can go through physical and changes, the amount of matter in those objects remains the same. This is known as t

he Law of Conservation of Matter. Matter can be broken into smaller pieces, dissolve in liquids, change physical states, and undergo other changes while still conserving its mass. Which pairs of matter demonstrate the law of conservation?
Chemistry
1 answer:
Liula [17]3 years ago
4 0
The question above is incomplete, the options attached tot he question are given below:
A. A structure made of building blocks.

 The blocks of the same structure bundled in a pile.

B.  A snowman.

 The melted remains of the same snowman.

C. A lump of clay.

The same lump broken into three pieces.

D. 1 cup of water and one gram of salt, separated.

 The same cup of water with one gram of salt mixed in.

E. One apple.

 The same apple cut into slices.

ANSWER:

The correct options are these:

B. A Snowman and the melted remain of the same snowman.

C. Lump of clay and the same clay broken into three pieces.

E. One apple and the same apple cut into slices.

For all the three answers listed above, the mass of the pairs will remain the same because nothing has been taken out of them and nothing is added to them, they were just changed from one form to another. The other options are wrong because, something got added to the original material. 

 

 


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What is the mass of 3.00 moles of magnesium chloride, MgCl2? Express your answer with the appropriate units.
xenn [34]
<span>To find the mass of 3.00 moles of magnesium chloride (MgCl2), first record the atomic mass of magnesium (Mg) and chloride (Cl), which are both listed on the periodic table as follows: Mg=24 g/mole Cl=38 g/mole Now, double the Cl mass since there are 2 Cl moles in MgCl2 and then add it to the Mg mass like so: (38 g/mole*2 moles)+24 g/mole=100 g/mole Finally, to calculate the mass of 3.00 moles of MgCl2, convert the combined atomic mass to grams as follows: 3.00 moles * 100 g/mole = 300 g</span>
5 0
3 years ago
Charles is given two electrical conductors – aluminium and graphite. Help him to select one for making an electric wire. Justify
Iteru [2.4K]

Answer: aluminum I think

Explanation:

6 0
3 years ago
A 0.1 gram sample of an unknown liquid is vaporized completely at 70 degrees C to fill a 750mL flask. The pressure is 0.05951atm
Deffense [45]

Answer:

The molar mass of the liquid 62.89 g/mol

Explanation:

Step 1: Data given

Mass of the sample = 0.1 grams

Temperature = 70°C

Volume = 750 mL

Pressure = 0.05951 atm

Step 2: Calculate the number of moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒ with n = the number of moles gas = TO BE DETERMINED

⇒ with p = The pressure = 0.05951 atm

⇒ with V = The volume of the flask = 750 mL = 0.750 L

⇒ with R = The gasconstant = 0.08206 L*atm/K*mol

⇒with T = the temperature = 70 °C = 343 Kelvin

n = (0.05951 *0.750)/(0.08206*343)

n = 0.00159 moles

Step 3: Calculate molar mass

Molar mass = mass / moles

Molar mass =0.1 gram /  0.00159 moles

Molar mass = 62.89 g/mol

The molar mass of the liquid 62.89 g/mol

6 0
3 years ago
2. Suppose that 21.37 mL of NaOH is needed to titrate 10.00 mL of 0.1450 M H2SO4 solution.
AysviL [449]

Answer:

0.1357 M

Explanation:

(a) The balanced reaction is shown below as:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

(b) Moles of H_2SO_4 can be calculated as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For H_2SO_4 :

Molarity = 0.1450 M

Volume = 10.00 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10×10⁻³ L

Thus, moles of H_2SO_4 :

Moles=0.1450 \times {10\times 10^{-3}}\ moles

Moles of H_2SO_4  = 0.00145 moles

From the reaction,

1 mole of H_2SO_4 react with 2 moles of NaOH

0.00145 mole of H_2SO_4 react with 2*0.00145 mole of NaOH

Moles of NaOH = 0.0029 moles

Volume = 21.37 mL = 21.37×10⁻³ L

Molarity = Moles / Volume = 0.0029 /  21.37×10⁻³  M = 0.1357 M

7 0
3 years ago
Lead (II) nitrate reacts with ammonium carbonate to produce ammonium nitrate
vitfil [10]

Pb(NO₃)₂ + (NH₄)₂CO₃ → PbCO₃ + 2 NH₄NO₃

Explanation:

Reaction of lead (II) nitrate with ammonium carbonate will produce lead (II) carbonate and ammonium nitrate.

The balanced chemical equation is:

Pb(NO₃)₂ + (NH₄)₂CO₃ → PbCO₃ + 2 NH₄NO₃

To balance the chemical equation the number of atoms of each element   entering the reaction have to be equal to the number of atoms of each   element leaving the reaction, in order to conserve the mass.

Learn more about:

balancing chemical reactions

brainly.com/question/13911443

#learnwithBrainly

3 0
3 years ago
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