A 125g steel ball with a kinetic energy of .25j rolls along a horizontal track how high up an inclined track will the ball roll
1 answer:
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Answer:
Explanation:
The equation for centripetal acceleration is .
We know the wheel turns at 45 rpm, which means 0.75 revolutions per second (dividing by 60), so our frequency is f=0.75Hz, which is the inverse of the period T.
Our velocity is the relation between the distance traveled and the time taken, so is the relation between the circumference and the period T, then we have:
Putting all together:
The Moment of Inertia of the Disc is represented by . (Correct answer: A)
Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:
(1)
Where:
- Moment of inertia of the Disk.
- Moment of inertia of the Hole.
Then, this formula is expanded as follows:
(1b)
Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole ():
And the resulting equation is:
The moment of inertia of the Disc is represented by . (Correct answer: A)
Please see this question related to Moments of Inertia: brainly.com/question/15246709