Question

A(n) 0.576 kg soccer ball approaches a player horizontally with a speed of 20.9 m/s. The player illegally strikes the ball with her hand and causes it to move in the opposite direction with a speed of 9.73 m/s. What is the magnitude of the impulse delivered to the ball by the player?

Answer 1

Answer:

17.6kg.m/s in the opposite direction of the initial velocity.

Explanation:

In order to solve this we can use the Impulse-Momentum theorem:

$J=\Delta p\\J=m(v_f-v_o)$

We will assume the motion of the ball approaching the player as positive, so:

$J=0.576kg((-9.73m/s)-20.9m/s)=-17.6kg.m/s$

So the impulse is 17.6kg.m/s in the opposite direction of the initial velocity.