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iren [92.7K]
2 years ago
6

A 2.5-liter sample of a gas has 0.30 mole of the gas. If 0.15 mole of the gas is added, what is the final volume of the gas? Tem

perature and pressure remain constant.
Chemistry
1 answer:
enot [183]2 years ago
4 0

Answer:

1.125

Explanation:

I think it is his because if you add 0.30 and 0.15 it adds up to 0.45 so you just multiply 0.45 and 2.5 and then it gives you 1.125. HOPE IT HELPS.

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Which statement is true?
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The statement that is true is that B. Atoms always remain intact during chemical reactions.

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It should be noted that atoms always remain intact during chemical reactions. They cannot be added and removed when there are <em>chemical reactions.</em>

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The air all around us is a mixture of gasses containing nitrogen, oxygen, carbon dioxide, argon
KiRa [710]

Answer:

Total pressure = 4.57 atm

Explanation:

Given data:

Partial pressure of nitrogen = 1.3 atm

Partial pressure of oxygen = 1824 mmHg

Partial pressure of carbon dioxide = 247 torr

Partial pressure of argon = 0.015 atm

Partial pressure of water vapor = 53.69 kpa

Total pressure = ?

Solution:

First of all we convert the units other into atm.

Partial pressure of oxygen = 1824 mmHg / 760 = 2.4 atm

Partial pressure of carbon dioxide = 247 torr / 760 = 0.325 atm

Partial pressure of water vapor = 53.69 kpa / 101 = 0.53 atm

Total pressure = Partial pressure of N +  Partial pressure of O +  Partial pressure of CO₂ +  Partial pressure of Ar +  Partial pressure of water vapor

Total pressure = 1.3 atm + 2.4 atm + 0.325 atm + 0.015 atm + 0.53 atm

Total pressure = 4.57 atm

4 0
3 years ago
El cation en el CaS​
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Answer:

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7 0
3 years ago
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If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount
nirvana33 [79]

<u>Answer:</u> The volume of water required is 398 mL

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (manganese (II) nitrate tetrahydrate) = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Molarity of solution = 0.16 M

Putting values in above equation, we get:

0.16M=\frac{16g\times 1000}{251g/mol\times \text{Volume of solution}}\\\\\text{Volume of solution}=398mL

Hence, the volume of water required is 398 mL

7 0
3 years ago
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