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mariarad [96]
1 year ago
9

An empty vial weighs 55.32 g.

Chemistry
1 answer:
ziro4ka [17]1 year ago
7 0

The answer is: Volume of mercury = 9.63 cm^3.

Density (d) is defined as mass of substance divided by its volume. Thus, if mass and density are known, then Volume can be determined.

What is the formula of volume in terms of density?

  • Let mass of substance be 'm' and volume be 'V'. Thus, as per the definition of density, it is expressed as-

d =\frac{m}{V}

  • Thus, volume can be expressed as-

V = \frac{m}{d}

  • Now, mass of empty vial= 55.32 g and the mass of  (vial+ mercury) = 185.56 g.

Thus, mass of mercury =185.56\ g- 55.32\g = 130.24\ g

  • Thus, mass of mercury = 130.24 g and density of mercury =13.53\ g/cm^3. Its volume is calculated as-

V =\frac{130.24\ g}{13.53\ g/cm^3}  = 9.63\ cm^3

  • Hence, volume of mercury = 9.63 cm^3.

To learn more about Density and Volume, visit:

brainly.com/question/1028144

#SPJ4

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Mumz [18]
The two notations that represent isotopes of the same element is the one that represented in option 1
The lower number is the number of protons while the upper number is the atomic weight

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6 0
2 years ago
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50g nitrous oxide combines with 50g oxygen form dinitrogen tetroxide according to the balanced equation below.
photoshop1234 [79]

Limiting reactant : O₂

Mass of  N₂O₄ produced = 95.83 g

<h3>Further explanation</h3>

Given

50g nitrous oxide

50g oxygen

Reaction

2N20 + 302 - 2N204

Required

Limiting reactant

mass of N204 produced

Solution

mol N₂O :

\tt =\dfrac{50}{44}=1.136

mol O₂ :

\tt =\dfrac{50}{32}=1.5625

2N₂O+3O₂⇒ 2N₂O₄

ICE method

1.136    1.5625

1.0416  1.5625    1.0416

0.0944    0          1.0416

Limiting reactant : Oxygen-O₂

Mass N₂O₄(MW=92 g/mol) :

\tt =mol\times MW=1.0416\times 92=95.83~g

7 0
3 years ago
how would I create a BCA chemistry table for this? I believe i started it right but i’m unsure of the rest.
kotykmax [81]
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3 years ago
The air at the top of Mount Everest has pressures of 201.0 torr N2, 50.0 torr O2, 2.0 torr Ar, and 0.5 torr CO2. What is the tot
nordsb [41]

Answer:

The total air pressure at the top of the highest peak in the world is 253.5 torr

Explanation:

The partial pressures of the gases present at the top of Mount Everest are;

Nitrogen, N₂ = 201.0 torr

Oxygen, O₂ = 50.0 torr

Argon, Ar = 2.0 torr

Carbon dioxide, CO₂ = 0.5 torr

By Dalton's law of partial pressure, the total pressure that a mixture of gases exerts is equal to the sum of the partial pressures of the individual gases

Mathematically, the law can be expressed as follows;

Total pressure, P = ∑P_i = P₁ + P₂ + · · ·

From which we have;

The total air pressure at the top of the highest peak in the world, Mount Everest, P_{Total Mont Everest} = The sum of the partial pressures of N₂, O₂, Ar, and CO₂

P_{Total Mont Everest} = 201.0 torr + 50.0 torr + 2.0 torr + 0.5 torr = 253.5 torr

P_{Total Mont Everest} = 253.5 torr = 0.33355263 atmosphere

Therefore, the total air pressure at the top of the highest peak in the world,  P_{Total Mont Everest} = 253.5 torr

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How does Kinetic energy and how does it relates to diffusion and temperature.
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Answer:

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