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GaryK [48]
3 years ago
11

What’s the correct answer !!

Chemistry
1 answer:
Sati [7]3 years ago
6 0

Answer:

From my side the correct option is "A"

Explanation:    Reasons for its correction are ,

1)  Highly reactive: Nanoparticles are therefore extremely unstable and easily change themselves or react with active substances to reach a relatively stable state in some cases. This causes desired changes or undesired changes to nanoparticles and thus makes them exhibit a high reactivity and a poor stability.

2)Small size:  Nanotechnology can provide rapid and sensitive detection of cancer-related molecules, enabling scientists to detect molecular changes even when they occur only in a small percentage of cells. Nanotechnology also has the potential to generate entirely novel and highly effective therapeutic agents.

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An aqueous solution of barium hydroxide is standardized by titration with a 0.102 M solution of perchloric acid. If 10.3 mL of b
Vesna [10]

<u>Answer:</u> The molarity of barium hydroxide solution is 0.118 M.

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HClO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ba(OH)_2

We are given:

n_1=1\\M_1=0.102M\\V_1=24.0mL\\n_2=2\\M_2=?M\\V_2=10.3mL

Putting values in above equation, we get:

1\times 0.102\times 24.0=2\times M_2\times 10.3\\\\M_2=0.118M

Hence, the molarity of Ba(OH)_2 solution will be 0.118 M.

6 0
2 years ago
If 200. g of water at 20°C absorbs 41 840 J of energy, what will its final temperature be? (Specific Heat of water is 4.184 J/g*
Elena-2011 [213]

Answer: The final temperature will be 70^0C

Explanation:

To calculate the specific heat of substance during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed =41840 J

c = specific heat = 4.184J/g^0C

m = mass of water  = 200 g

T_{final} = final temperature =?

T_{initial}= initial temperature = 20^0C

Now put all the given values in the above formula, we get:

41840J=200g\times 4.184J/g^0C\times (T_{final}-20)^0C

T_{final}=70^0C

Thus the final temperature will be 70^0C

3 0
3 years ago
A sample of metal has a mass of 18.20g, and a volume of 7.38mL. What is the density in g/cm^3?
AlexFokin [52]
Density = Mass ÷ Volume. You get 2.466
8 0
3 years ago
Describe the characteristics of the moon and the Earth for each phase of the
Yuri [45]
Before we describe the phases of the Moon, let's describe what they're not. Some people mistakenly believe the phases come from Earth's shadow cast on the Moon. Others think that the Moon changes shape due to clouds. These are common misconceptions, but they're not true. Instead, the Moon's phase depends only on its position relative to Earth and the Sun.

The Moon doesn't make its own light, it just reflects the Sun's light as all the planets do. The Sun always illuminates one half of the Moon. Since the Moon is tidally locked, we always see the same side from Earth, but there's no permanent "dark side of the Moon." The Sun lights up different sides of the Moon as it orbits around Earth – it's the fraction of the Moon from which we see reflected sunlight that determines the lunar phase.
6 0
3 years ago
If a sample of oxygen gas originally at from 171.4 K has its temperature increased to 288.4 K and
julia-pushkina [17]

Answer:

V₂ = 0.95 L

Explanation:

Given data:

Initial temperature of gas = 171.4 K

Final temperature of gas = 288.4 K

Final volume = 1.6 L

Initial volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₂ = 1.6 L × 171.4 K / 288.4 k

V₂ = 274.24 L.K / 288.4 K

V₂ = 0.95 L

6 0
3 years ago
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