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saveliy_v [14]
2 years ago
8

What are the elements names for C9H8O4

Chemistry
1 answer:
pochemuha2 years ago
7 0
C9 is Carbon with 9 atoms
H8 is Hydrogen with 8 atoms
O4 is oxygen with 4 atoms
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2.4 Propene reacts with steam to produce an alcohol, propanol.
qaws [65]

Answer:

C₃H₆ + H₂O = C₃H₈O

Explanation:

Hydration reactions (reactions involving converting an alkene to alcohol) have only one product, so there will be no byproduct along with propanol.

7 0
3 years ago
The elements that touch the zigzag line are classified as
svp [43]

On the periodic table everything to the right of the line is a non metal

Everything to the left is a metal. So the line crosses to the right is NM to left is M

5 0
3 years ago
A certain organic compound is made up of the amino acids methionine, arginine, and leucine. Which type of organic compound is th
Andrews [41]

<em>Answer:</em>

  • The protein is an organic compound which is made up of the amino acids methionine, arginine, and leucine etc. 

<em>Explanation:</em>

  • Most of the amino acid are linked with others amino acid through peptide linkage to form proteins. The peptide bond is formed between the two amino acid involving carboxylic and amino group.
  • The proteins produce by this way may be simple, conjugated and derived proteins.


4 0
3 years ago
Read 2 more answers
1. A helium-filled balloon had a volume of 8.50 L on the ground at 20.0°C and a
maw [93]

Answer:

133.74 L

Explanation:

First we <u>convert the given pressures and temperatures into atm and K</u>, respectively:

  • 750.0 Torr ⇒ 750/760 = 0.9868 atm
  • 20°C ⇒ 20+273.16 = 293.16 K
  • 40°C ⇒ 40+273.16 = 313.16 K

Then we<u> use the PV=nRT formula to calculate the number of moles of helium in the balloon</u>, using<em> the data of when it was on the ground</em>:

  • 0.9868 atm * 8.50 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 293.16 K
  • n = 2.866 mol

Then, knowing the value of n, we <u>use PV=nRT once again, this time to calculate V</u> using <em>the data of when the balloon was high up:</em>

  • 0.550 atm * V = 2.866 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 313.16 K
  • V = 133.74 L
5 0
3 years ago
4. Evaluate the information contained in this calculation and complete the
Neporo4naja [7]

Since you did not give a calculation, I will just give an example. Suppose that you are to burn 5 kg of methane (CH4) from 0 to 10°C. The specific heat capacity of methane is 4.475 kJ/kg-K.

H = mCpT

H = (5kg)( 4.475 kJ/kg-K)(10-0)

H = 223.75 kJ

Because the enthalpy is positive in value, methane takes in heat. 

7 0
4 years ago
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