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Sindrei [870]
3 years ago
8

Can somebody please help me? PLEASE

Physics
1 answer:
ale4655 [162]3 years ago
6 0

Answer:

The 1st Answer

Explanation:

Because kinetic energy is the energy which a body possesses by virtue of being in motion. So if the velocity of the object (cannonball in this case) decreases than so would the kinetic energy

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Answer:

.3 repeating hours

Explanation:

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2 years ago
Which of the following elements do living things have that volcanic rocks don’t have? A) Oxygen B) Silicon C) Magnesium D) Carbo
Mrrafil [7]
Either A or D. If I were answering I'd go with my git answer and say A
5 0
3 years ago
PLEASE PROVIDE EXPLANATION.<br><br> THANK YOU!!
Ksju [112]

Answer:

11,000 kg

(a) 11.2 m/s

(b) 1.6 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(2200 kg) (60.0 km/h) + m (0 km/h) = (2200 kg) (10 km/h) + m (10 km/h)

132,000 kg km/h = 22,000 kg km/h + m (10 km/h)

110,000 kg km/h = m (10 km/h)

m = 11,000 kg

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(m) (-v) + (2m) (5v) = (m) (v₁) + (2m) (v₂)

-mv + 10mv = m v₁ + 2m v₂

9mv = m (v₁ + 2 v₂)

9v = v₁ + 2 v₂

Since the collision is elastic, kinetic energy is also conserved.

½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²

m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²

(m) (-v)² + (2m) (5v)² = m v₁² + (2m) v₂²

mv² + 50mv² = m v₁² + 2m v₂²

51mv² = m (v₁² + 2 v₂²)

51v² = v₁² + 2 v₂²

We know v = 1.60 m/s.  So the two equations are:

14.4 = v₁ + 2 v₂

130.56 = v₁² + 2 v₂²

Solve the system of equations using substitution.

130.56 = (14.4 − 2 v₂)² + 2 v₂²

130.56 = 207.36 − 57.6 v₂ + 4 v₂² + 2 v₂²

0 = 6 v₂² − 57.6 v₂ + 76.8

0 = v₂² − 9.6 v₂ + 12.8

v₂ = [ 9.6 ± √(9.6² − 4(1)(12.8)) ] / 2(1)

v₂ = 1.6 or 8

If v₂ = 1.6 m/s, then v₁ = 14.4 − 2 v₂ = 11.2 m/s.

If v₂ = 8 m/s, then v₁ = 14.4 − 2 v₂ = -1.6 m/s.

We know v₁ can't be -1.6 m/s, since that would mean puck A didn't change speeds after the collision.  Therefore, v₁ = 11.2 m/s and v₂ = 1.6 m/s.

8 0
3 years ago
A small lead ball, attached to a 1.70-m rope, is being whirled in a circle that lies in the vertical plane. The ball is whirled
Otrada [13]

Answer:

H = 54.37

Explanation:

given,

lead ball attached at = 1.70 m

rate of revolution = 3 revolution/sec

height above the ground = 2 m

velocity = \dfrac{distance}{time}

circumference of the circle = 2 π r

                                             = 2 x π x 1.7

                                             = 10.68 m

velocity = \dfrac{3 \times 10.68}{1}

v = 32.04 m/s

using conservation of energy

\dfrac{1}{2}mv^2 + mgh = mgH

\dfrac{1}{2}v^2 + gh = gH

\dfrac{1}{2}32.04^2 + 9.8\times 2 = 9.8\times H

532.88 = 9.8\times H

H = 54.37

the maximum height reached by the ball is equal to H = 54.37

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3 years ago
A cheetah, which is the fastest land mammal, can accelerate at 9 m/s from rest to in 31 m/s. How long does
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31 m/s ÷ 9 m/s² = 3.44 s

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