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Sindrei [870]
2 years ago
8

Can somebody please help me? PLEASE

Physics
1 answer:
ale4655 [162]2 years ago
6 0

Answer:

The 1st Answer

Explanation:

Because kinetic energy is the energy which a body possesses by virtue of being in motion. So if the velocity of the object (cannonball in this case) decreases than so would the kinetic energy

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I shared a picture of the problem. It’s a basic Physics question and an Algebra question.
julia-pushkina [17]

Hence the expression of ω in terms of m and k is

\omega = \sqrt{\frac{k}{m}

Given the expressions;

T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}

Equating both expressions we will have;

2 \pi \sqrt{\frac{m}{k} }  = \frac{2 \pi}{\omega}

Divide both equations by 2π

\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\

Square both sides

(\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}

Take the square root of both sides

\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}

Hence the expression of ω in terms of m and k is

\omega = \sqrt{\frac{k}{m}

3 0
3 years ago
If, while standing on the bank of a stream, you wished to spear a fish swimming in the water out in front of you, would you aim
Serggg [28]

Answer:

<em>a) below the observed position</em>

<em>b) directly at the observed position</em>

<em></em>

Explanation:

If I'm standing on the bank of a stream, and I wish to spear a fish swimming in the water out in front of me, I would aim below the observed fish to make a direct hit. This is because the phenomenon of refraction of light in water causes the light coming from the fish is refract away from the normal as it passes  into the air and into my eyes.

If I'm to zap the fish with a taser, I would aim directly at the observed fish because the laser (a form of concentrated light waves) will refract into the water, taking the same path the light from the fish took to get to my eyes.

3 0
3 years ago
An airplane flies 20km in a direction 60 degrees north of east, then 30 km straight east, then 10km straight north. How far and
Fed [463]

Answer:

48.4 km, 34.3° north of east

Explanation:

Let's say east is the +x direction and north is the +y direction.

Adding up the x components of the vectors:

x = 20 cos 60 + 30 + 0

x = 40 km

Adding up the y components of the vectors:

y = 20 sin 60 + 0 + 10

y = 27.3 km

The magnitude of the displacement is:

d = √(x² + y²)

d = 48.4 km

The direction is:

θ = atan(y/x)

θ = 34.3° north of east

6 0
3 years ago
A motor-driven winch pulls a 50.0 kg student 5.00 m up the rope at a constant speed of 1.25 m/s. how much power does the motor u
nadya68 [22]
Power is the rate work done given by dividing work done by unit time. It is measured in watts equivalent to J/s.
In this case the force by the student is mg = 490 N (taking g as 9.8m/s²)
Work done is given by force × distance,
Therefore, Power =(force × distance)/ time, but velocity/speed =distance/time
Thus, Power = force × speed/velocity
                     = 490 N × 1.25
                     = 612.5 J/S (Watts)
Hence, power will be 612.5 Watts.
7 0
3 years ago
Could someone please help me with this question?​
Elenna [48]
1 because the the mid night summer is dark
3 0
3 years ago
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