Answer:
value of the acceleration of gravity on the planet is 5.00 m/s²
Explanation:
The problem is similar to a free fall exercise, with another gravity value, the expression they give us is the following:
y-yo = ½ gₐ t² (1)
They tell us that they make a squared time graph with the variation of the distance, it is appropriate to clarify this in a method to linearize a curve, which is plotted the nonlinear axis to the power that is raised, specifically, the linearization of a curve The square is plotted against the other variable.
Let's continue our analysis, as we have a linear equation, write the equation of the line.
y1 = m x1 + b (2)
where “y1” the dependent variable, “x1” the independent variable, “m” the slope and “b” the short point
In this case as the stone is released its initial velocity is zero which implies that b = 0,
We plot on the “y” axis the time squared “t²” and on the horizontal axis we place “y-yo”. To better see the relationship we rewrite equation 1 with this form
t² = 2 /gₐ (y-yo)
With the two expressions written in the same way, let's relate the terms one by one
y1 = t²
x1 = (y-yo)
m = 2/gap
b= 0
We substitute and calculate
m = 2/gp
gₐ = 2/m
gₐ = 2/ 0.400
gₐ = 5.00 m / s²
This is the value of the acceleration of gravity on the planet, note that the decimals are to keep the figures significant
