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oee [108]
3 years ago
12

Write three sentences that provide evidence supporting your claim about how the illustration and student observations support th

e cell theory?
Chemistry
1 answer:
Ksenya-84 [330]3 years ago
5 0

Answer:

The cell theory claims these three components:

1. cell is the smallest functional unit of life: It can be observed under the microscope that cells have various type of molecules and organelles present and have adifferent functional role in the cell which explains that the cell is the smallest unit of life as its molecules or organelles can not carry the life process on their own.

2. All organisms are made up of cells: From bacteria and archaea to human and other life forms are made up of a single cell or organization of cells in a specific pattern it also can be observed by the microscopic of blood or other tissue or cell of an organism.

3. Arise from pre-existing cell: The cells are can be studied under a microscope during cell division where we can observe that new cells come from the pre existing cell by the cell division.

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a normal hemoglobin concentration in the blood is 15g/100ml of blood how many kilogram of hemoglobin are in a person who has 5.5
jok3333 [9.3K]
Using stoichiometry:

5.5 L of blood x (1000 mL/1L) x (15 g/100 mL) x (1 kg/1000 g) = 0.825 kg
4 0
3 years ago
Read 2 more answers
In a classical long run supply model the economy is always doing what
ch4aika [34]

Answer:

Economy is always at the full employment level of output

Explanation:

The economy in a classical long-run supply model will always have the same economic output

8 0
3 years ago
Match each element to the number of electrons in its valence shell
blondinia [14]

Answer: Be= 2, C =4,  Li = 1 and  B=3

Explanation:

The valence shell can be define as the outermost shell of an atom that contains the valence electrons.

Beryllium (Be), electronic configuration; 1s2 2s2, = 2 electrons in its valence shell.

Carbon (C), electronic configuration; 1s2 2s2 2p2, = 4 electrons in its valence shell.

Lithium (Li), electronic configuration; 1s2 2s1 = 1 electron in its valence shell.

Boron (B) , electronic configuration; 1s2 2s2 2p1 = 3 electron in its valence shell.

6 0
3 years ago
Why is it important for scientists to use a classification
Kobotan [32]
So they can tell what exact species it is. 
7 0
3 years ago
he rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate c
Leya [2.2K]

The question is incomplete, here is the complete question:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

<u>Answer:</u> The rate constant at 324°C is 61.29M^{-1}s^{-1}

<u>Explanation:</u>

To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:

\ln(\frac{K_{324^oC}}{K_{244^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{244^oC} = equilibrium constant at 244°C = 6.7M^{-1}s^{-1}

K_{324^oC} = equilibrium constant at 324°C = ?

E_a = Activation energy = 71.0 kJ/mol = 71000 J/mol   (Conversion factor:  1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 244^oC=[273+244]K=517K

T_2 = final temperature = 324^oC=[273+324]K=597K

Putting values in above equation, we get:

\ln(\frac{K_{324^oC}}{6.7})=\frac{71000J}{8.314J/mol.K}[\frac{1}{517}-\frac{1}{597}]\\\\K_{324^oC}=61.29M^{-1}s^{-1}

Hence, the rate constant at 324°C is 61.29M^{-1}s^{-1}

8 0
4 years ago
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