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3 years ago

12

what is the energy change if an ice cube of mass 50 grams (initially at it's normal melting point) was converted to steam at the

normal boiling point or water?

1 answer:

Kipish [7]3 years ago

8 0

I think it is evaporation hope this helped

You might be interested in

Baking soda and antacid tablets are examples of two common__________

attashe74 [19]

Bases

A base is a substance that dissociates into more hydroxide ions (-OH-) when dissolved in water. Bases are also good proton acceptors. Bases, therefore, reduce the number of H+ and increase OH- hence raising the pH of the solution.

B(aq) + H₂O(l) ⇌ BH⁺(aq) + OH⁻(aq)

Explanation:

Other properties of bases is that they are bitter to the taste and they feel slippery when touched. Strong bases are nonthlese very corrosive like acids. Bases turn red litmus paper blue. Most alkali hydroxides such as NaOH are bases.

Learn More:

For more on bases check out;

brainly.com/question/12574229

brainly.com/question/2015251

#LearnWithBrainly

7 0

3 years ago

In reality, energy conversion from burning fuel is never 100% efficient. Significant loss of energy due to heating occurs. If th

algol [13]

Answer:

Electrical energy = 130000000 J and Heat energy = 520000000 J

Explanation:

Multiply the amount of joules from the last question (650000000) by .20 and .80. (Which are the percentages)

6 0

2 years ago

A buffer solution contains 0.479 M NaHCO3 and 0.342 M Na2CO3. Determine the pH change when 0.091 mol HNO3 is added to 1.00 L of

pshichka [43]

Answer:

ΔpH = 0.20

Explanation:

The buffer of HCO₃⁻ + CO₃²⁻ has a pka of 10.2

HCO₃⁻ ⇄ H⁺ + CO₃²⁻

There are 0.479moles of NaHCO₃ and 0.342moles of Na₂CO₃.

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.342mol / 0.479mol

<em>pH = 10.05</em>

NaOH reacts with HCO₃⁻ producing CO₃²⁻, thus:

NaOH + HCO₃⁻ → CO₃²⁻ + H₂O + Na⁺

0.091 moles of NaOH produce the same moles of CO₃²⁻ and consume HCO₃⁻. Moles of these species are:

CO₃²⁻: 0.342mol + 0.091mol: 0.433mol

HCO₃⁻: 0.479mol - 0.091 mol: 0.388mol

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.433mol / 0.388mol

pH = 10.25

That means change of pH, ΔpH is:

ΔpH = 10.25 - 10.05 = <em>0.20</em>

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I hope it helps!

3 0

2 years ago

The production of ammonia (NH3) under standard conditions at 25°C is represented by the following thermochemical equation. N2(g)

asambeis [7]

Answer:

44,901 kilo Joule heat is released when $1.663\times 10^4 g$ grams of ammonia is produced.

Explanation:

Moles of ammonia gas produced :

$\frac{1.663\times 10^4 g}{17 g/mol}=978.235 mol$

According to reaction, when 2 moles of ammonia are produced 9.18 kilo joules of energy is also released.

So, When 978.235 moles of ammonia gas is produced the energy released will be:

$\frac{-91.8 kJ}{2}\times 978.235 mol=-44,900.98 kJ\approx -44,901 kJ$

(negative sign indicates that energy is released as heat)

44,901 kilo Joule heat is released when $1.663\times 10^4 g$ grams of ammonia is produced.

7 0

3 years ago

How much work does the climber do on his pack if his pack weighs 90 N and he climbs to a height of 30 m?

Vladimir79 [104]

Answer:

2,700j

Explanation:

yupppppppp

8 0

3 years ago