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mote1985 [20]
3 years ago
10

The term 10 points and brainlyess

Chemistry
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0

Answer:

water cycle

Explanation:

if this is a one word term, i dont know but otherwise it is water cycle. hope this helps

Sonbull [250]3 years ago
8 0

Answer:

Mate! Water Cycle would be your answer.

Hope it helps!

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10 points get it right ADVPH
Sav [38]

Answer:

Advanced Pharmaceutics Inc

Explanation:

Advanced Pharmaceutics Inc

somehow I know this acroynom

8 0
3 years ago
Which of the following is least likely to dissolve in the polar solvent water?
s2008m [1.1K]
<span>Like dissolves like and unlike repels like. This applies to the polarity of the solutions. Polar dissolves polar and non-polar does not mix with polar solutions. In this case, the polar substance that can mix with water. Sugar and salt can be dissolved through agitation. Oil which is nonpolar is immiscible in water. Hence answer is D. </span>
6 0
3 years ago
If you have a 4.6 L of gas in a piston at a pressure of 1.2 atm and compress the gas unit it's volume is 2.6 L, what will the ne
klio [65]

Answer:

<h3>The answer is 2.12 atm</h3>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

So we have

P_2 =  \frac{4.6 \times 1.2}{2.6}  =  \frac{5.52}{2.6}  \\  = 2.1230769...

We have the final answer as

<h3>2.12 atm</h3>

Hope this helps you

8 0
3 years ago
Jeffrey wants to lose weight by using caffeine to
irinina [24]

Answer:

4. The amount of caffeine in the drinks

5. The heart rate of the participants of the experiments

6. Water

7. i) The volume of drink taken should be constant

ii) The frequency of taking their drink is constant

iii) The time of drinking by the brothers is constant

Explanation:

In the question, Jeffery intends to find the caffeine drink that will result in the heart rate increasing most

The variables (varieties) of drinks tested by Jeffery = Pepsi, espresso, and water

Drink variable arranged by the order of increasing Caffeine content are presented as follows;

Caffeine content of water < Caffeine content of Pepsi < Caffeine content of espresso

The triplet with the double shot of espresso = The triplet with the highest heart rate

4. The independent variable is the variable which is suspected to be the cause of the specified observation

Therefore, in the question, the independent variable are the drinks with different amount of caffeine

5. The dependent variable is the effect or the outcome of the independent variable

The dependent variable in the question is the heart rate of the subjects in the study

6. The control group is the independent variable or input that is expected to give the minimum effect or output compared to other independent variables in the study such that the control group does not contain the suspected cause of the observation or effect under investigation

The control group (or variable) in the question is water which does not contain caffeine

7. Three constants that all three brothers should be doing are;

i) The three brothers should be taking a constant or the same quantity of their preferred drink

ii) The frequency at which they take their drinks should be constant

iii) The time at which the brothers take the drink should be the same

3 0
3 years ago
40.00 mL of 0.10 M KOH solution is titrated by 30.00 mL of 0.10 M HCl (adding HCl to KOH). What is the pH of the solution in the
Natali5045456 [20]

Answer:

pH=12.16

Explanation:

<u>The alkaline solution: </u>

40 ml of 0.1 M KOH

n_{KOH}=\frac{1 L}{1000mL}*40mL*0.1M=0.004 mol

<u>The acid solution: </u>

30 ml of 0.1 M HCl

n_{HCl}=\frac{1 L}{1000mL}*30mL*0.1M=0.003 mol

The neutralization reaction:

HCl + KOH \longrightarrow KCl + H_2O

For 1 mol of HCl, 1 mol of KOH is consumed. If 0.003 mol of HCl are added, 0.003 mol of KOH reacted.

After titration:

n_{KOH}=0.001 mol

n_{HCl}= 0 mol

Concentration (don't forget to add the volumes)

n_{KOH}=\frac{1 1000mL}{1L *70mL}*0.001 mol=0.0143 mol

Calcualtion of the pOH:

pOH=-log([OH^-])=-log(0.0143)=1.84

For the pH:

pH=14-pOH=14-184=12.16

4 0
3 years ago
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