Answer: See attached image
Explanation:
Answer:
Approximately 
, assuming that this acid is monoprotic.
Explanation:
Assume that this acid is monoprotic. Let 
denote this acid.
.
Initial concentration of without any dissociation:
![[{\rm HA}] = 0.730\; \rm mol \cdot L^{-1}](https://tex.z-dn.net/?f=%5B%7B%5Crm%20HA%7D%5D%20%3D%200.730%5C%3B%20%5Crm%20mol%20%5Ccdot%20L%5E%7B-1%7D)
.
After 
of that was dissociated, the concentration of both 
and 
(conjugate base of this acid) would become:
.
Concentration of in the solution after dissociation:
.
Let ![[{\rm HA}]](https://tex.z-dn.net/?f=%5B%7B%5Crm%20HA%7D%5D)
, ![[{\rm H}^{+}]](https://tex.z-dn.net/?f=%5B%7B%5Crm%20H%7D%5E%7B%2B%7D%5D)
, and ![[{\rm A}^{-}]](https://tex.z-dn.net/?f=%5B%7B%5Crm%20A%7D%5E%7B-%7D%5D)
denote the concentration (in 
or 
) of the corresponding species at equilibrium. Calculate the acid dissociation constant 
for , under the assumption that this acid is monoprotic:
![\begin{aligned}K_{\rm a} &= \frac{[{\rm H}^{+}] \cdot [{\rm A}^{-}]}{[{\rm HA}]} \\ &= \frac{(0.09125\; \rm mol \cdot L^{-1}) \times (0.09125\; \rm mol \cdot L^{-1})}{0.63875\; \rm mol \cdot L^{-1}}\\[0.5em]&\approx 1.30 \times 10^{-2} \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7DK_%7B%5Crm%20a%7D%20%26%3D%20%5Cfrac%7B%5B%7B%5Crm%20H%7D%5E%7B%2B%7D%5D%20%5Ccdot%20%5B%7B%5Crm%20A%7D%5E%7B-%7D%5D%7D%7B%5B%7B%5Crm%20HA%7D%5D%7D%20%5C%5C%20%26%3D%20%5Cfrac%7B%280.09125%5C%3B%20%5Crm%20mol%20%5Ccdot%20L%5E%7B-1%7D%29%20%5Ctimes%20%280.09125%5C%3B%20%5Crm%20mol%20%5Ccdot%20L%5E%7B-1%7D%29%7D%7B0.63875%5C%3B%20%5Crm%20mol%20%5Ccdot%20L%5E%7B-1%7D%7D%5C%5C%5B0.5em%5D%26%5Capprox%201.30%20%5Ctimes%2010%5E%7B-2%7D%20%5Cend%7Baligned%7D)
.
When an atom of the element lithium (Li) transfers an electron to an atom of the element fluorine (F), then the bond results between the atoms is ionic bond.
<h3>what is chemical bond? </h3>
A chemical bond is defined as the bond which holds atoms together in molecules.
Bonds arise due to the electrostatic forces present between positively charged atomic nuclei and negatively charged electrons.
<h3>Types of chemical bond</h3>
- Ionic bond
- Covalent bond
- Coordinate bond
<h3>What is Ionic bond ? </h3>
Ionic bond is defined as the transfer of electron from one atom to another atom.
Since, electron transfer from lithium to fluroine. Thus lithium get positive charge and fluorine occupy negative charge.
Thus, the bond form between lithium atom and fluorine atom is ionic bond.
learn more about ionic bond:
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Answer : A metal atom loses electrons from its outermost energy level and acquires a Positive Charge. These electrons join a nonmetal atom. The ionic compound formed because of this transfer of electrons is electrically Neutral.
Explanation :
All the elements try to acquire octet state by gaining or losing electrons. For metals, the number of valence electrons are less and it is easier to lose these electrons.
When electrons are lost, the number of protons become more than the electrons. This creates an excess of positive charge. As a result the species becomes positively charged and is known as cation.
During formation of ionic bond, metals always form a positive ion (cation) by losing electrons. These electrons are accepted by the nonmetals and they become negatively charged. A negatively charged ion is known as anion and nonmetals always form an anion.
These are attracted to each other due to the opposite charges present on them. In an ionic compound they balance the charges on each other making the compound neutral.
From the above discussion, we can fill in the blanks as follows.
A metal atom loses electrons from its outermost energy level and acquires a Positive Charge. These electrons join a nonmetal atom. The ionic compound formed because of this transfer of electrons is electrically Neutral.
The molarity is 31.0 * x / 2, such that x is the molar mass of Ca₃(PO₄)₂
