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Aleksandr [31]
2 years ago
5

Calculate the volume of chlorine molecules produced at room temperature and pressure, when 234g of sodium chloride are electroly

sed. (1 mole of chlorine molecules has a volume of 24 dm³ at room temperature and pressure).​
Chemistry
1 answer:
rewona [7]2 years ago
4 0

The volume of chlorine molecules produced at STP would be 96 dm³.

<h3>Stoichiometric problem</h3>

Sodium chloride ionizes during electrolysis to produce sodium and chlorine ions as follows:

NaCl --- > Na^+ + Cl^-

This means that 1 mole of sodium chloride will produce 1 mole of sodium ion and 1 mole of chlorine ion respectively.

Recall that: mole = mass/molar mass

Hence, 234 g of sodium chloride will give:

                         234/58.44 = 4.00 moles.

Thus, the equivalent number of moles of chlorine produced by 234 g of sodium chloride will be 4 moles.

Recall that:

1 mole of every gas at Standard Temperature and Pressure = 24 Liters.

Hence:

4 moles of chlorine = 4 x 24 = 96 Liters or 96 dm³.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

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3. From the following formula, calculate the quantities required to make 5 lb o hydrophilic ointment. Methylparaben 0.25 g Propy
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The given question is incomplete. The complete question is as follows.

From the following formula, calculate the quantities required for each of the following ingredients to make 5 lb. (avoir) of hydrophilic ointment. All values to be in g, do not include units in your submitted answer; use no more than 3 decimal places. Convert using 1 lb = 454 g. Note: all values done by mass, including the water, so this is not a q.s situation (volume is irrelevant).

Methylparaben 0.25 g

Propylparaben 0.15 g

Sodium Lauryl Sulfate 10 g

Propylene Glycol 120 g

Stearyl Alcohol 240 g

White Petrolatum 250 g

Purified Water, to make 1000 g

Explanation:

For the given quantities, the sum is 620.4 g. Now, amount of purified water (to make 1000 g of ointment)  is as follows.

             1000 g - 620.4 g

           = 379.6 g

Now, to make 5 lb we will calculate the quantities as follows.

Formula weight = 1000 g

Therefore, desired quantity is as follows.

             5 lb = 5 x 454 g

                     = 2270 g

Hence, this means the factor is  calculated as follows.

       \frac{2270 g}{1000 g}

            = 2.27

Now, we will calculate the quantity of each ingredient using factor 2.27 as follows.

  • Methylparaben = 0.25 g x 2.27 = 0.5675 g
  • Propylparaben = 0.15 g x 2.27 = 0.3405 g
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  • Propylene Glycol = 120 g x 2.27 = 272.4 g
  • Stearyl Alcohol = 240 g x 2.27 = 544.8 g
  • White Petrolatum = 250 g x 2.27 = 567.5 g
  • Purified Water = 379.6 g x 2.27 = 861.692 g
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