What are gizmos explain and I will help you
Answer:
0.086J/g°C
Explanation:
The following data were obtained from the question:
Mass (M) = 30g
Initial temperature (T1) = 10°C
Final temperature (T2) = 45°C
Change in temperature (ΔT) = T2 – T1 = 45°C – 10°C = 35°C
Heat (Q) released = 90J
Specific heat capacity (C) of wood =..?
We can obtain the specific heat capacity of the wood as follow:
Q = MCΔT
90 = 30 x C x 35
Divide both side by 30 x 35
C = 90/(30 x 35)
C = 0.086J/g°C.
Therefore, the specific heat capacity of the wood is 0.086J/g°C.
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GREETINGS!</h2><h2>
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Answer:</h3>
ITS 
AND 
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GENERAL FORMULA OF ALKANE</u></h3><h3>
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Where n is the number of CARBONS
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A)
By using the General Formula of Alkanes having 4 carbon atoms is
C)
By using the General Formula of Alkanes having 5 carbon atoms is
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IF YOU USE THE SAME FORMULA FOR THE OTHER TWO OPTIONS THE OUTCOME WILL NOT BE AS SAME AS GIVEN IN THE QUESTION SO THOSE TWO ARE CAN NOT BE OUR ANSWER
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HOPE THIS HELPS!</h2>
Answer:
Both student have same percent error.
Explanation:
Given data:
Actual mass of object = 0.54 g
Measured value by one student = 0.59 g
Measured value by second student = 0.49 g
Percent error = ?
Solution:
Formula
Percent error = (measured value - actual value / actual value) × 100
Percent error of first student:
percent error = (0.59 g - 0.54 / 0.54 ) ×100
percent error = 9.3 %
Percent error of second student:
Percent error = (0.49 g - 0.54 / 0.54 ) ×100
Percent error = - 9.3 %
Both student have same percent error. The only difference is that first student measure the greater value then actual value and second student measure the less value then actual, however difference was same and gives same percent error.
Answer:
Explanation:
<u>1) Data:</u>
a) [OH⁻] = 2.1 × 10⁻⁶ M . . . (the symbol g shown in the question is a typo)
b) pH = ?
<u>2) Formulae:</u>
<u>3) Solution:</u>
- pOH = log ( 1 / 2.1 × 10⁻⁶ ) = 5.7
- pH = 14 - pOH = 14 - 5.7 = 8.3
