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Radda [10]
3 years ago
12

How much would the temperature of 275 g of water increase if 36.5 kj of heat were added?

Chemistry
2 answers:
Andrew [12]3 years ago
8 0

<u>Answer:</u> The temperature increase will be 31.70°C.

<u>Explanation:</u>

To calculate the increase in the temperature of the system, we use the equation:

q=mc\Delta T

where,

q = Heat absorbed = 36.5 kJ = 36500J

m = Mass of water = 275 g

c = Specific heat capacity of water = 4.186J/g^oC

\Delta T = change in temperature = ? °C

Putting values in above equation, we get:

36500J=275\times 4.186J/g^oC\times \Delta T\\\\\Delta T=31.70^oC

Hence, the temperature increase will be 31.70°C.

BlackZzzverrR [31]3 years ago
8 0
<span>The solution is found using the formula change in Temperature = heat supplied/ (mass of substance x specific heat). The solution would be change in temperature = 36.5kJ/(275 g x 4.184 J/g) = 31.7 degrees.</span>
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Explanation:

The flame test is a widely used qualitative analysis method to identify the presence of a certain chemical element in a sample. To carry it out you must have a gas burner. Usually a Bunsen burner, since the temperature of the flame is high enough to carry out the experience (a wick burner with an alcohol tank is not useful). The flame temperature of the Bunsen burner must first be adjusted until it is no longer yellowish and has a bluish hue to the body of the flame and a colorless envelope. Then the tip of a clean platinum or nichrome rod (an alloy of nickel and chromium), or failing that of glass, is impregnated with a small amount of the substance to be analyzed and, subsequently, the rod is introduced into the flame, trying to locate the tip in the least colored part of the flame.

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3 years ago
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