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3 years ago

How much would the temperature of 275 g of water increase if 36.5 kj of heat were added?

Chemistry

2 answers:

Andrew [12]3 years ago

8 0

<u>Answer:</u> The temperature increase will be 31.70°C.

<u>Explanation:</u>

To calculate the increase in the temperature of the system, we use the equation:

$q=mc\Delta T$

where,

q = Heat absorbed = 36.5 kJ = 36500J

m = Mass of water = 275 g

c = Specific heat capacity of water = $4.186J/g^oC$

$\Delta T$ = change in temperature = ? °C

Putting values in above equation, we get:

$36500J=275\times 4.186J/g^oC\times \Delta T\\\\\Delta T=31.70^oC$

Hence, the temperature increase will be 31.70°C.

BlackZzzverrR [31]3 years ago

8 0

<span>The solution is found using the formula change in Temperature = heat supplied/ (mass of substance x specific heat). The solution would be change in temperature = 36.5kJ/(275 g x 4.184 J/g) = 31.7 degrees.</span>

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