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Radda [10]
3 years ago
12

How much would the temperature of 275 g of water increase if 36.5 kj of heat were added?

Chemistry
2 answers:
Andrew [12]3 years ago
8 0

<u>Answer:</u> The temperature increase will be 31.70°C.

<u>Explanation:</u>

To calculate the increase in the temperature of the system, we use the equation:

q=mc\Delta T

where,

q = Heat absorbed = 36.5 kJ = 36500J

m = Mass of water = 275 g

c = Specific heat capacity of water = 4.186J/g^oC

\Delta T = change in temperature = ? °C

Putting values in above equation, we get:

36500J=275\times 4.186J/g^oC\times \Delta T\\\\\Delta T=31.70^oC

Hence, the temperature increase will be 31.70°C.

BlackZzzverrR [31]3 years ago
8 0
<span>The solution is found using the formula change in Temperature = heat supplied/ (mass of substance x specific heat). The solution would be change in temperature = 36.5kJ/(275 g x 4.184 J/g) = 31.7 degrees.</span>
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