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Novosadov [1.4K]
4 years ago
13

WILL UPVOTE!!!Physics help please!!

Physics
1 answer:
liubo4ka [24]4 years ago
8 0
Speed v = initial speed u + acceleration a x time t 
v=u+at = 2 + 4*3 = 14 m/s

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a resistor, of resistance 47 , is damaged when it dissipates a power greater than 0.5W. determine the maximum voltage that can b
harkovskaia [24]

Answer:

<em>The maximum voltage that can be applied without damaging the resistor is 4.85 V</em>

Explanation:

<u>Electric Power in a Resistor</u>

Given a resistor or resistance R connected to a circuit of voltage V carrying a current I. The relation between these three magnitudes is given by Ohm's Law:

V = R.I

The dissipated power P of a resistor can be calculated by the following equation, known as Joule's first law:

P = I^2.R

Solving the first equation for I:

\displaystyle I=\frac{V}{R}

Substituting in the second equation:

\displaystyle P=\frac{V^2}{R^2}.R

Simplifying:

\displaystyle P=\frac{V^2}{R}

Solving for V:

V=\sqrt{P.R}

The resistor has a resistance of R=47Ω and can hold a maximum power of P=0.5 W, thus the maximum voltage is:

V=\sqrt{0.5\cdot 47}

V=\sqrt{23.5}

V = 4.85 V

The maximum voltage that can be applied without damaging the resistor is 4.85 V

6 0
3 years ago
A crane raises a crate with a mass of 150 kg to a height of 20 m. Given that
Virty [35]

Answer:

\boxed {\boxed {\sf 29,400 \ Joules}}

Explanation:

Gravitational potential energy is the energy an object possesses due to its position. It is the product of mass, height, and acceleration due to gravity.

E_P= m \times g \times h

The object has a mass of 150 kilograms and is raised to a height of 20 meters. Since this is on Earth, the acceleration due to gravity is 9.8 meters per square second.

  • m= 150 kg
  • g= 9.8 m/s²
  • h= 20 m

Substitute the values into the formula.

E_p= 150 \ kg \times 9.8 \ m/s^2 \times 20 \ m

Multiply the three numbers and their units together.

E_p=1470 \ kg*m/s^2 \times 20 m

E_p=29400 \ kg*m^2/s^2

Convert the units.

1 kilogram meter square per second squared (1 kg *m²/s²) is equal to 1 Joule (J). Our answer of 29,400 kg*m²/s² is equal to 29,400 Joules.

E_p= 29,400 \ J

The crate has <u>29,400 Joules</u> of potential energy.

7 0
3 years ago
A pendulum of length L = 1 m is released from an initial angle of 15° . After 1000 s, its amplitude is reduced to 2.5º. What is
jonny [76]

Answer:

The value of the time constant is 558.11 sec.

Explanation:

Given that,

Pendulum length = 1 m

Initial angle = 15°

Time = 1000 s

Reduced amplitude = 2.5°

We need to calculate the value of the time constant

Using formula of damping oscillation

\theta=\theta_{0}e^{\dfrac{t}{\tau}}

Where, \theta =amplitude

\theta_{0} =amplitude at t = 0

Put the value into the formula

2.5=15e^{\dfrac{-1000}{\tau}}

\dfrac{1}{6}=e^{\dfrac{-1000}{\tau}}

ln\dfrac{1}{6}=\dfrac{-1000}{\tau}

\tau=\dfrac{1000}{-ln\dfrac{1}{6}}

\tau=558.11\ sec

Hence, The value of the time constant is 558.11 sec.

6 0
3 years ago
A sample contains 10g of radioactive isotope. How much radioactive isotope will remain in the sample after 3 half-lives?
Ainat [17]

Answer:

After 1 half-life (500 years), 500 g of the parent isotope will remain. After 2 half-lives (1000 years), 250 g of the parent isotope will remain. After 3 half-lives (1500 years), 125 g of the parent isotope will remain. After 4 half-lives (2000 years), 62.5 g of the parent isotope will remain.

Explanation:

3 0
3 years ago
2H2+O2---&gt; 2H2O can be classified as what type of reaction?
alisha [4.7K]
I believe the answer is B
3 0
4 years ago
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