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2 years ago

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How many joules of heat are required to heat 25.0 g of isopropyl alcohol from the prevailing room temperature, 21.2 oC, to its b

oiling point, 82.4 oC? The specific heat of isopropyl alcohol is 2.604 J/g °C.

1 answer:

valentinak56 [21]2 years ago

7 0

Answer:

3984.12 J joules of heat are required to heat 25.0 g of isopropyl alcohol to its boiling point.

Explanation:

$Q=m\times c\Delta T=m\times c\times (T_2-T_1)$

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

$T_1$ = Initial temperature of the substance

$T_2$ = Final temperature of the substance

We have mass of isopropyl alcohol = m = 25.0 g

Specific heat of isopropyl alcohol = c = 2.604 J/g°C

Initial temperature of the isopropyl alcohol = $T_1=21.2^oC$

Final temperature of the isopropyl alcohol = $T_2=82.4 ^oC$

Heat absorbed by the isopropyl alcohol to boil:

$Q=25.0 g\times 2.604 J/g^oC\times (82.4^oC-21.2^oC)=3984.12 J$

3984.12 J joules of heat are required to heat 25.0 g of isopropyl alcohol to its boiling point.

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3 years ago

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if 100. mL of 0.800 M Na2SO4 is added to 200. mL of 1.20 M NaCl, what is the concentration of Na+ ions in the final solution? As

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Compounds Na₂SO₄ and NaCl are mixed together are we are asked to find the concentration of Na⁺ in the mixture
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1 mol of Na₂SO₄ gives out 2 mol of Na⁺ ions

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3 years ago

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$\: 1.237 \times 10^{23} molecules \: of \:I _{2} \: are$

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The overall balanced equation for the reaction is,

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$Number \: of \: moles \: ofCuCl_{2}=0.4235 \: mol$

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$1 \: mole \: of \: I_{2} \: = 6.022 \times 10 ^{23} \: molecules \: of I_{2}$

So, the number of molecules produced in the reaction of

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$= \frac{0.4235 \times 6.022 \times 10 ^{23} }{2 }$

$= 1.237 \times 10^{23} \: molecules \:$

$1.237 \times 10^{23} \: molecules \: of \: I_{2} \: are \:$

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$Mass \: of \: I _{2} \: produced \: are \: is ,$

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$53.74 \: g \: of \: I _{2} \: produced \: in \: the \:$

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$Therefore , \: 1.237 \times 10^{23} molecules$

$of \: I_{2} \: are\: produced \: and \: 53.74 \: g \: of$

are produced in the reaction.

To know more about moles, refer to the below link:

brainly.com/question/26416088

#SPJ4

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