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3 years ago

10

If 21.3 grams of lithium react with excess water, how many liters of hydrogen gas can be produced at 297 kelvin and 1.40 atmosph

eres?

1 answer:

Tamiku [17]3 years ago

5 0

Hope it cleared your doubt :)

You might be interested in

What is a positive ion?

BaLLatris [955]

Answer:

If the atom has more electrons than protons, it is a negative ion or ANION. If it has more protons than electrons, it is a positive ion.

Explanation:

Positive ions are typically metals or act like metals. Many common materials contain these ions. Mercury is found in thermometers, for instance, and aluminum is a metal that is found in a surprising amount of things.

8 0

3 years ago

I need to know number 2 3 4 and 5

dexar [7]

Answer 2: 57.21235000000001

Answer 3: 44.01g

Answer 4: 24.645320000000005

Answer 5: 107.04578240000001

Good luck

7 0

3 years ago

What do these observations tell you about the rate and direction of heat flow through each specific type of plastic?

Murljashka [212]

Answer:

Heat is something you can't control

Explanation:

Plastic is something you could control like moving it around

3 0

2 years ago

Glycerol (molar mass 92.09 g/mol) has been suggested for use as an alternative fuel. The enthalpy of combustion, Δ

victus00 [196]

The mass of glycerol to that would need to be combusted to heat 500.0g of water from 20.0°C to 100.0°C is; 9.32 grams.

We must establish the fact that energy is neither created nor destroyed.

Therefore, the amount of heat absorbed by water is equal to the amount of heat released by the combustion of glycerol.

Total heat absorbed by water, H(water) is;

Q(water) = m C (T2 - T1)

Q(water) = 500 × 4.184 × (100-20)

Q(water) = 167.36 kJ

Consequently, the quantity of heat evolved by the combustion of glycerol is;

Q(glycerol) = 167,360 J = n × ΔH°comb

where, n = no. of moles of glycerol.

167.36 kJ= n × 1654 kJ/mole

n = 167.36/1654

n = 0.1012 moles of glycerol.

Therefore, mass of glycerol combusted, m is;

m = n × Molar mass

m = 0.1012 × 92.09

m = 9.32 g.

Read more:

brainly.com/question/20709115

6 0

3 years ago

1. A 225-L barrel of white wine has an initial free SO2 concentration of 22 ppm and a pH of 3.70. How much SO2 (in grams) should

Alexandra [31]

Answer:

The appropriate answer is "9.225 g".

Explanation:

Given:

Required level,

= 63 ppm

Initial concentration,

= 22 ppm

Now,

The amount of free SO₂ will be:

= $Required \ level -Initial \ concentration$

= $63-22$

= $41 \ ppm$

The amount of free SO₂ to be added will be:

= $41\times 225$

= $9225 \ mg$

∵ 1000 mg = 1 g

So,

= $9225\times \frac{1}{1000}$

= $9.225$

Thus,

"9.225 g" should be added.

3 0

3 years ago