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allochka39001 [22]
3 years ago
9

Which expression is equivalent to the given expression? -2.12 + 8r - 9 + 40 + 712 + 2 O A. 512 + 12r - 7 OB.5.12 + 4x + 11 O C.

-9.12 - 12r + 11 OD.-9.12 + 41 - 7​
Mathematics
1 answer:
cricket20 [7]3 years ago
7 0

Answer:

use microsoft maths solver

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MAXImum [283]

Answer:

B

Step-by-step explanation:

The heaviest pig on the farm weighs 100 pounds

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2 years ago
What fraction is equivalent to 5/9
Mama L [17]
1. Any fraction that you multiply the numerator by the same number as the denominator. 
Example:
1 x 2 = 2
-------------
2 x 2 = 4
2. The simplest form of 24/60 is 2/5 I believe.
3. 4/9
4. 23/8





Please vote me brainliest on this one too
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3 years ago
Help meh emergency. No links please give a right answer, need helppppp
andre [41]

Answer:

70.91 x 10 = 709.1

70.91 x 100 = 7,091

70.91 x 1000 = 70,910

8 0
3 years ago
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Please answer the following question. (40 points)
7nadin3 [17]

Answer:

80

Step-by-step explanation:

We have, 75% × x = 60

or,

75/ 100 × x = 60

Multiplying both sides by 100 and dividing both sides by 75,

we have x = 60 × 100/75

x = 80

4 0
2 years ago
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NEED ANSWERED ASAP WILL REWARD BRAINLIEST
Luda [366]

Answer:

The sum of the first 100 terms is 60400

Step-by-step explanation:

* Lets revise the arithmetic sequence

- There is a constant difference between each two consecutive

  numbers

- Ex:

# 2  ,  5  ,  8  ,  11  ,  ……………………….

# 5  ,  10  ,  15  ,  20  ,  …………………………

# 12  ,  10  ,  8  ,  6  ,  ……………………………

* General term (nth term) of an Arithmetic sequence:

- U1 = a  ,  U2  = a + d  ,  U3  = a + 2d  ,  U4 = a + 3d  ,  U5 = a + 4d

- Un = a + (n – 1)d, where a is the first term , d is the difference

 between each two consecutive terms n is the position of the

 number

- The sum of first n terms of an Arithmetic sequence is calculate from

 Sn = n/2[a + l], where a is the first term and l is the last term

* Now lets solve the problem

- We will use method (1)

- From the table the terms of the sequence are:

 10 , 22 , 34 , 46 , 58 , 82 , 94 , ............., where 10 is the first term

∵ an = a1 + (n - 1) d ⇒ explicit formula

∵ a1 = 10 and a2 = 22

∵ d = a2 - a1

∴ d = 22 - 10 = 12

- The 100th term means the term of n = 100

∴ a100 = 10 + (100 - 1) 12

∴ a100 = 10 + 99 × 12 = 10 + 1188 = 1198

∴ The 100th term is 1198

- Lets find the sum of the first 100 terms of the sequence

∵ Sn = n/2[a1 + an]

∵ n = 100 , a = 10 , a100 = 1198

∴ S100 = 100/2[10 + 1198] = 50[1208] = 60400

* The sum of the first 100 terms is 60400

7 0
3 years ago
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