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erma4kov [3.2K]
3 years ago
10

A chemist weighed out

Chemistry
1 answer:
Vikentia [17]3 years ago
6 0
No of moles= mass/atomic mass

no moles of potassium= 65g/39.8= 1.6moles
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Use the mass spectrum of rubidium to determine the atomic mass of rubidium.
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The mass spectrum is a visual graph that shows a Intensity vs Mass plot, like that shown in the picture. This is an actual mass spectrometer diagram for Rubidium. The mass of the isotopes of the Rb element is along the x-axis, while the y-axis is the relative abundance. The atomic mass is determined to be:

∑(Mass×Intensity) = 85(1-0.38) + 87(0.38) = 85.76 amu

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4 years ago
Which neutral element has the following electron configuration? 1 s^2 2s^2 2 p^6 3 s^2 3 p^41s ​2 ​​ 2s ​2 ​​ 2p ​6 ​​ 3s ​2 ​​
Orlov [11]
Sulfur, written as S.
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3 years ago
What is the coronavirus? Where was it first found in?
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3 years ago
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A 75.0 g sample of dinitrogen monoxide is confined in a 3.q L vessel. What is the pressure( in atm) at 115 celsius
Nonamiya [84]
Data Given:
                  Pressure  =  P  =  ?

                  Volume  =  V  =  3.0 L

                  Temperature  =  T  =  115 °C + 273  =  388 K

                  Mass  =  m  =  75.0 g

                  M.mass  =  M  =  44 g/mol

Solution:
              Let suppose the Gas is acting Ideally. Then According to Ideal Gas Equation,
                                      P V  =  n R T
Solving for P,
                                      P  =  n R T / V      ------ (1)
Calculating Moles,
                                      n  =  m / M

                                      n  =  75.0 g / 44 g.mol⁻¹

                                      n  =  1.704 mol

Putting Values in Eq. 1,

                    P  =  (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L

                    P  =  18.08 atm
7 0
3 years ago
Answer the following questions that relate to electrochemical reactions. (a) Under standard conditions at 25˚C, Zn(s) reacts wit
Elanso [62]

Answer:

0.48 V

Explanation:

Zn(s) ------------> Zn^2+(aq) + 2e. Oxidation half equation (-0.76V)

Co^2+(aq) + 2e-----------> Co(s). Reduction half equation (-0.28)

Zn(s) + Co^2+(aq) -------------> Zn^2+(aq) + Co(s) overall redox equation

Zinc is the anode while cobalt is the cathode.

E°cell= E°cathode - E°anode

E°cell= -0.28-(-0.76)= 0.48 V

7 0
4 years ago
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