Atom
Atom
Cathode rays
Neutron
Equal to
Protons
Subtract the atomic number
1
How many grams of solute do you have to weigh to prepare 250 ml KMnO4 solution with a concentration of 0.500 mol / L
Answer:
19.75g
Explanation:
Given parameters:
Volume of KMnO₄ = 250mL or 0.25L
Concentration of solution = 0.5mol/L
Unknown:
Mass of solute or KMnO₄ = ?
Solution:
To solve this problem, we need to find the number of moles first.
Number of moles = Concentration x volume
Number of moles = 0.5mol/L x 0.25L = 0.125mol
So;
Mass in grams = number of moles x molar mass
Molar mass of KMnO₄ = 39 + 55 + 4(16) = 158g/mol
Mass in grams = 0.125 x 158 = 19.75g
Hello!
The balanced equation for the
neutralization of KOH is the following:
HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)
To calculate the
volume of HCl required, we can apply the following equation:

So, the required volume of HCl is
541,54 mLHave a nice day!
Answer:
Mg + O2 ---> MgO
Explanation: V2O5 + CaS → CaO + V2S5. 5V2O5 + 5CaS → 10CaO + 5V2S5. 3V2O5 + 3CaS → 3CaO + 3V2S5.
Answer:
The number of protons also determines the identity of the element. ... Since the atom is electrically neutral, the number of electrons must equal the number of protons.