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Ray Of Light [21]
3 years ago
10

Consider the reaction Cl 2(g) + Br 2(g) <=> 2 BrCl(g), which is endothermic as written. What would be the effect on the eq

uilibrium position of increasing the temperature? 1. Reaction would go to the right, making more "products" 2. Reaction would go to the left, making more "products" 3. Reaction would go to the left, making more "reactants" 4. Reaction would go to the right, making more "reactants" 5. No change on the equilibrium position
Chemistry
2 answers:
olya-2409 [2.1K]3 years ago
6 0

Hey there!:

endothermic reaction can be represented by   :

A + heat  B

So when  temperature is decreased , the system tries to oppose the change. SO it moves to the side where the temperature increases. I f it moves to product side, the temperature decreases as it it absorbing heat to form products.

 

So the system moves to the reactants side.

Elodia [21]3 years ago
3 0

According to Le Châtelier's principle, an increase in temperature favors the endothermic process. Since the reaction, which proceeds towards bromine chloride, is endothermic, the reaction would shift right, making more products.

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Which diagram above has 4 valence electrons?
Gemiola [76]

Answer:

answer A has four valence electrons

Explanation:

The outer shell has 4 electrons, which are considered the valence electrons

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2 years ago
Olympic cyclists fill their tires with helium to make them lighter. Assume that the volume of the tire is 860 mL , that it is fi
nata0808 [166]

Answer:

a)  the mass of air = 8.24 grams

b) the mass of helium = 1.14 grams

c) the mass difference = 7.10 grams

Explanation:

Step 1: Data given

Volume of the tire = 860 mL

Total pressure = 120 psi

Temperature = 26°C

molar mass of air = 28.8 g/mol

Step 2:  Convert psi to atm

(

120 psi) (1 atm / 14.7 psi) = 8.163

Step 4: Calculate moles

PV = nRT

 ⇒ with P = the pressure = 8.163 atm

⇒ with V = the volume = 860 mL = 0.860 L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ with R = the universal gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 26 °C = 299 Kelvin

n = (8163*0.860)/(0.08206*299)

n = 0.2861 moles of gas

Step 5: Calculate the mass of air in an air-filled tire.

Mass = moles * molar mass

Mass = (0.2861 moles of gas) (28.8 g/mol)  

Mass = 8.24 grams

Step 6: Calculate the mass of helium in a helium- filled tire.

mass of helium = 0.2861 moles of gas * 4 g/mol)  

mass of helium  = 1.14 grams

Step 7: What is the mass difference between the two?

Δmass=  8.24 grams -  1.14 grams

Δmass= 7.10 grams

8 0
3 years ago
A compound decomposes by a first-order process. if 25.0% of the compound decomposes in 60.0 minutes, the half-life of the compou
Tom [10]
Answer:<span>d. 145 minutes
</span>
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Nt= N0 (1/2)^ t/h

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N0= the initial mass
t= time passed
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If 25.0% of the compound decomposes that means the final mass would be 75% of initial mass. Then the half-live for the compound would be:
Nt= N0 (1/2)^ t/h
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3/4= 1/2^(60min/h)
log2 3/4 = log2 1/2^(60min/h)
0.41503749928 = -60min/h
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3 years ago
Substances that cannot be separated and found on a periodic table
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Substances that cannot be separated and found on a periodic table are elements.


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Answer:

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