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3 years ago

What is answer to this question

Mathematics

1 answer:

avanturin [10]3 years ago

4 0

2912 glasses of water

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PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.

Liula [17]

Answer:

$\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}$

Step-by-step explanation:

$\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)$

$\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)$

7 0

3 years ago

Read 2 more answers

I need help plsss help

Fed [463]

Answer:

Triangle: True

Parallelogram: False, area is 63cm^2

Trapezoid: True

Step-by-step explanation:

Use area calculators on the internet to find the area of shapes.

3 0

3 years ago

Will give 25 points and brainliest answer if correct

Norma-Jean [14]

Let $d$ be the common difference between terms in the sequence $\{a_n\}_{n\ge1}$ . Then

$a_{19}=-58$
$a_{20}=a_{19}+d$
$a_{21}=a_{19}+2d$
$\implies-164=-58+2d\implies d=-53$

The first term in the sequence, $a_1$ , satisfies

$a_2=a_1+d$
$a_3=a_1+2d$
$a_4=a_1+3d$
...
$a_{19}=a_1+18d$
$\implies-58=a_1+18(-53)\implies a_1=896$

So the explicit formula for the $n$ -th term in the sequence is

$a_n=a_1+(n-1)d\implies a_n=896-53(n-1)$

5 0

3 years ago

Help me again pls and who ever gets it correct gets 20 points plus brainliest

Ostrovityanka [42]

Answer:just drag across

Step-by-step explanation:

4 0

2 years ago

What is "the quotient of a number and 12." In number form?

kykrilka [37]

Answer:

x/12

Step-by-step explanation:

4 0

3 years ago