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nevsk [136]
3 years ago
11

What's us the volume. first answer get brainliest answer​

Mathematics
2 answers:
Bogdan [553]3 years ago
6 0

Answer:

200+90 =290 m^3

Step-by-step explanation:

Find the volume of the box on the bottom

V = l*w*h

V = 8*5*5 = 200 m^3

Find the volume of the box on the top

V = l*w*h

V = 3*6*5 = 90 m^3

Add the volumes together to get the total volume

200+90 =290 m^3

Crazy boy [7]3 years ago
5 0

Answer:

290m^3

Step-by-step explanation:

the rectangular prism on top: 3mx6mx5m = 90m^3

the rectangular prism on bottom: 5mx5mx8m = 200m^3

add both: 200m^3+90m^3 = 290m^3

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6×4×5 = 120 in^3; 12×8×10 = 960 in^3; Prism B's volume is 8 times greater than Prism A's volume
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Find the length of the third side. If necessary, write in simplest radical form.
Mazyrski [523]

Answer:

\boxed {\boxed {\sf 8}}

Step-by-step explanation:

This triangle has a small square, which represents a right angle. Therefore, we can use the Pythagorean Theorem.

a^2+b^2=c^2

Where <em>a</em> and <em>b </em> are the legs of the triangle and <em>c</em> is the hypotenuse.

In this triangle, 7 and √15 are the legs, because these sides make up the right angle. The unknown side is the hypotenuse, because it is opposite the right angle. So, we know two values:

a= 7 \\b= \sqrt{15}

Substitute these values into the formula.

(7)^2+(\sqrt{15})^2=c^2

Solve the exponents.

  • (7)²= 7*7=49

49+ (\sqrt{15})^2=c^2

  • (√15)²=√15*√15=15

49+15=c^2

Add.

64=c^2

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

\sqrt{64}=\sqrt{c^2} \\\sqrt{64}= c\\8=c

The third side length is <u>8.</u>

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Which of the following statements are true about the triangles?
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The quotient of a number and 2 is equal to 50​
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Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6
Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

a)

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" =  [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL =  0 ( SET TO ZERO )

Diagram of the Chart uploaded below

b)

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

so

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL  = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0  ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

7 0
2 years ago
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