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dedylja [7]
3 years ago
14

Can someone pls help me with this?

Physics
1 answer:
alexira [117]3 years ago
6 0
C because they are both going in a constant speed
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Describe how different types of motion are represented by distance-time graphs and velocity-time graphs.
eduard

Answer:

non-accelerated movement

velocity versus time  a horizontal straight line.

distance versus time  gives a horizontal straight line.

accelerated motion

graph of velocity versus time s an inclined line and the slope

graph of distance versus time is a parabola of the form

Explanation:

In kinematics there are two types of steely and non-accelerated movements

In a  the velocity of the body is constant therefore a speed hook against time gives a horizontal straight line.

A graph of distance versus time is a straight line whose slope is the velocity of the body

          x = v t

In an accelerated motion the velocity changes linearly with time, so a graph of velocity versus time is an inclined line and the slope is the value of the acceleration of the body

         v = v₀ + a t

A graph of distance versus time is a parabola of the form

         x =v₀ t + ½ a t²

4 0
3 years ago
9/10 in percents. Examples please, at least 2.
Len [333]

Answer:

90/100%, 9/10%

Explanation:

These represent 9 of 10 parts.

Hope this answer helps you out.

8 0
3 years ago
Read 2 more answers
1. If the angle of the ramp were increased from 30˙ to 45˙, how would this change the weight of the box? Explain.
yawa3891 [41]

When the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

<h3>Normal reaction of the box</h3>

The normal reaction of the box is due to weight of the box acting perpendicular to the ramp.

Fn = Wcosθ

<h3>when the angle of the ramp = 30⁰</h3>

Fn = Wcos(30)

Fn = 0.866W

<h3>when the angle of the ramp = 45⁰</h3>

Fn = W x cos(45)

Fn = 0.7071W

Thus, when the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

Learn more about normal reaction here: brainly.com/question/18292235

#SPJ1

4 0
2 years ago
Object A attracts object B with a gravitational force of 10 newtons from a given distance. If the distance between the two objec
balandron [24]

By definition, the gravitational force is given by:

F = G(\frac{m1m2}{r^2})

Where,

G: gravitational constant

m1: mass of object 1

m2: mass of object 2

r: distance between objects:

We know that the force is equal to 10N:

G(\frac{m1m2}{r^2}) = 10

If the distance is double we have:

F = G(\frac{m1m2}{(2r)^2}) = G(\frac{m1m2}{4r^2}) = \frac{1}{4}G(\frac{m1m2}{r^2})

\frac{1}{4}(10) = 2.5

Therefore, the new force is:

2.5 newtons

Answer:

the changed force of attraction between them is:

A. 2.5 newtons

7 0
3 years ago
Read 2 more answers
A small cylinder made of a diamagnetic material is brought near a bar magnet. One end of the cylinder is brought near the North
FromTheMoon [43]

Answer: Option (A) is the correct answer.

Explanation:

A diamagnetic material does not contain any unpaired electrons and therefore, in a magnetic field direction they will always flow in the direction opposite to the magnetic field.

Hence, a diamagnetic material will always repel the magnetic field whenever it comes in contact with that.

Thus, we can conclude that when the other end of the cylinder is brought near the North pole of the magnet then the other end of the cylinder will be repelled by the magnet.

6 0
4 years ago
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