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3 years ago

Can someone pls help me with this?

Physics

1 answer:

alexira [117]3 years ago

6 0

C because they are both going in a constant speed

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Anyone know this? PLEASE HELP, I just want to get this exam finished with ):

IceJOKER [234]

Answer:

Explanation:

4 0

3 years ago

Two 10 kg pucks head straight towards each other with velocities of 10 m/s and -20 m/s. They collide and stick together. Calcula

RUDIKE [14]

The final velocity of the two pucks is -5 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum.

In fact, in absence of external force, the total momentum of the two pucks before and after the collision must be conserved - so we can write:

$m_1 u_1 + m_2 u_2 = (m_1 +m_2)v$

where

$m_1 = m_2 = m = 10 kg$ is the mass of each puck

$u_1 = 10 m/s$ is the initial velocity of the 1st puck

$u_2 = -20 m/s$ is the initial velocity of the 2nd puck

v is the final velocity of the two pucks sticking together

Re-arranging the equation and solving for v, we find:

$mu_1 + mu_2 = (m+m)v\\u_1 + u_2 = 2v\\v=\frac{u_1+u_2}{2}=\frac{10-20}{2}=-5 m/s$

Learn more about momentum:

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8 0

3 years ago

A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the bal

Snowcat [4.5K]

Answer:

78 N s

Explanation:

The impulse exerted on the ball is given by:

$I = F \Delta t$

where

F is the magnitude of the force

$\Delta t$ is the duration of the collision

In this problem,

F = 39 N

$\Delta t = 2 s$

Substituting,

$I=(39 N)(2 s)= 78 Ns$

5 0

3 years ago

A spherical drop of water carrying a charge of 38 pC has a potential of 710 V at its surface (with V = 0 at infinity). (a) What

Hitman42 [59]

Answer: a) r= 4.82 * 10^-4 m ; b) 1420 V

Explanation: In order to solve this problem we have to take into account that potential for a sphere respec to V=0 at the infinity, which is given by:

V=k*Q/r where r is the radius of the drop

then we have

r=k*Q/V=9*10^9*38pC/710V= 4.82 * 10^-4 m

Finally if we join two drop to form one with the same radius but with twice charge the resultant potential is:

V= k*2*Q/(r)= 710*2= 1420 V

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4 years ago

How would the attractive force between two spheres change if the mass of one sphere was doubled?

Dominik [7]

The force of attraction between two objects can be illustrated using Newton's Law of Universal Gravitation.
The relation between the different parameters is shown in the attached image.

Now, from the relation, we can deduce that the force between the two objects is directly proportional to the masses of the two objects.

This means that, if the mass of one object is doubled, then the force between the two objects will also be doubled.

8 0

3 years ago