Answer:
You left out the quantity of grams remaining.
Step-by-step explanation:
We have the following function:
f (x) = 3/8 (4) ^ x
The function is of the form:
f (x) = A (b) ^ x
Where,
A: initial amount
b: growth factor (b> 1)
x: time variable.
Answer:
f (x) = 3/8 (4) ^ x
It is an exponential function of the form:
f (x) = A (b) ^ x
Line BC passes through (-5,5) and (0 ,1)
Slope = 5-1/-5-0 = -4/5
Line BC cuts the y-axis at (0,1)
⇒ y-intercept must be 1
General Equation of a linear line: y = mx + b
Plug m = -4/5 and b = 1 into the general equation and find the equation of line BC:
y = -4/5x + 1
Multiply by 5 on both sides:
5y = -4x + 5
Add 4x to both sides:
4x + 5y = 5
Answer: 4x + 5y = 5 (Option C)
Answer:
42
Step-by-step explanation:
in order to find y, we need to find x.
180-65-62=53
x=53
we need to subtract 53-?=11
53-42=11
y=42
Answer:
Given :The monthly demand for a product is normally distributed with mean = 700 and standard deviation = 200.
To Find :
1. What is probability demand will exceed 900 units in a month?
2. What is probability demand will be less than 392 units in a month?
Solution:
We are supposed to find probability demand will exceed 900 units in a month.
Formula :
We are supposed to find P(Z>900)
Substitute x = 900
Refer the z table.
P(Z<900)=0.8413
P(Z>900)=1-P{(Z<900)=1-0.8413=0.1587
So, the probability that demand will exceed 900 units in a month is 0.1587.
Now we are supposed to find probability demand will be less than 392 units in a month
We are supposed to find P(Z<392)
Substitute x = 392
refer the z table
P(Z<900)=0.0618
So, probability that demand will be less than 392 units in a month is 0.0618.