The GPS (Global Positioning System) satellites are approximately 5.18 mm across and transmit two low-power signals, one of which
is at 1575.42 MHz (in the UHF band). In a series of laboratory tests on the satellite, you put two 1575.42 MHz UHF transmitters at opposite ends of the satellite. These broadcast in phase uniformly in all directions. You measure the intensity at points on a circle that is several hundred meters in radius and centered on the satellite. You measure angles on this circle relative to a point that lies along the centerline of the satellite (that is, the perpendicular bisector of a line which extends from one transmitter to the other). At this point on the circle, the measured intensity is 2.00 W/m^2.
Required:
What is the intensity at a point on the circle at an angle of 4.45° from the centerline?
Required:
What is the intensity at a point on the circle at an angle of 4.45° from the centerline?
1 answer:
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Answer:
The potential energy when it reads 40 N is
Explanation:
From the question we are told that
The lowest reading of the spring balance is 0 N and this is at 0 cm = 0 m
The height reading of the spring balance is 60 N and this is at 20 cm = 0.20 m
Generally the length corresponding to the reading of 40 N is mathematically represented as
=>
Generally the potential energy is mathematically represented as
Here
So
=>