Answer:
power is 35.5 W
power is 1.06 W
power is 1.06 W
Explanation:
Given data
R = 23.5 Ω
L = 396 mH
C = 49.5 μF
voltage = 29 V
solution
we know that in 1st part power that is equal to square of current × R
so
power = I²R
so current I = V/Z = 29/23.5 because R = Z at resonance
current = 1.23 A
power = 1.23²×23.5
power = 35.5 W
and
in 2nd part we know that frequency that is
f = 1/2π × √(1/LC)
f = 1/2(3.14) × √(1/396×10^-3×49.5×10^-6)
f = 35.94 Hz
so power = I²R
here
I = V/Z
Z = √( R² + (x - y)²)
x = 2π(2f) L
x = 2(3.14)× ( 2×35.94)×( 396×
x = 178.84 ohm
y = 1 / 2π(2f) C
y = 1 / 2(3.14)× ( 2×35.94)×( 49.5×
y = 44.73 ohm
so
Z = √( 23.5² + (178.84 - 44.73)²)
Z = 136.15 ohm
so current = 29 / 136.15
current I = 0.212 A
so power = 0.212² / 136.15
power = 1.06 W
and
in 3rd part same like 2nd
frequency = 35.94 Hz and X = 2π(2f) L = 2(3.14)× ( 35.94/2)×( 396×
X = 44.71 ohm
Y = 1 / 2π(2f) C = 1 / 2(3.14)× ( 35.94/2)×( 49.5×
Y = 178.98 ohm
so Z = √( 23.5² + (44.71 - 178.98)²)
Z = 136.25 ohm
current = 29 / 136.25
current = 0.212 A
so power = 0.212² / 136.15
power = 1.06 W
Power is determined by work/time.
We have P = W/T as our formula.
There is 375J of work, and 11s of time.
Plug in 375J for Work, and 11s for Time.
P = 375/11
Our power is 34.09.
Hope this helps!
Answer:
The mass of the banana is m and it is at height h.
Applying the Law of Conservation of Energy
Total Energy before fall = Total Energy after fall
=
Here, total energy is the sum of kinetic energy and potential energy
+
=
+
(a)
When banana is at height h, it has
= 0 and
= mgh
and when it reaches the river, it has
= 1/2m
and
= 0
Putting the values in equation (a)
0 + mgh = 1/2m
+ 0
mgh = 1/2m
<em>cutting 'm' from both sides</em>
<em> </em>gh = 1/2
v = 
Hence, the velocity of banana before hitting the water is
v = 
The answer to this is Freon :D