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3 years ago

Find the inverse of the function f f (x ) equals 9 x + 7

Mathematics

1 answer:

MrMuchimi3 years ago

6 0

Note: Your question seems a little bit ambiguous. So, I am assuming the given function f(x)=9x+7.

Thus, I am solving based on it. It would still clear your concept.

Answer:

The inverse of f(x)=9x+7

$\frac{x-7}{9}$

Step-by-step explanation:

Given the function

$f(x)=9 x + 7$

A function g is the inverse of function f if for y=f(x), x=g(y)

Replace x with y

$x=9y+7$

solve for y

$9y=x-7$

$y=\:\frac{x-7}{9}$

Therefore,

The inverse of f(x)=9x+7 is:

$\frac{x-7}{9}$

i.e.

$\mathrm{Inverse\:of}\:9x+7:\quad \frac{x-7}{9}$

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Solve each proportion. 2/8=5/r+8

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Answer:

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Step-by-step explanation:

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3 years ago

What is the answer -8 + 3 + -8 – -3

Sophie [7]

-8+3+-8--3
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3 years ago

Read 2 more answers

Find three consecutive whose sum 237

Nina [5.8K]

Answer:

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Step-by-step explanation:

Let the smallest number = x

Let the next number = x + 1

Let the largest number = x + 2

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3x + 3 = 237 Subtract 3 from both sides.

3x + 3 - 3 = 237 - 3 Combine the right

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3 years ago

Read 2 more answers

(03.05 MC) Solve the rational equation x divided by 2 equals x squared divided by quantity x minus 2 end quantity, and check for

ycow [4]

Answer:

x = 0 and x = -2 are solutions of the given rational equation.

Step-by-step explanation:

We must solve the following rational equation:

$\frac{x}{2} = \frac{x^{2}}{x-2}$

Now we present the procedure:

1) $\frac{x}{2} = \frac{x^{2}}{x-2}$ Given

2) $x\cdot (x-2) = 2\cdot x^{2}$ Compatibility with multiplication/Existence of the multiplicative inverse/Definition of division/Modulative property.

3) $x^{2}-2\cdot x = 2\cdot x^{2}$ Distributive property/ $a^{b}\cdot a^{c} = a^{b+c}$

4) $x^{2} + 2\cdot x = 0$ Compatibility with addition/Existence of the additive inverse/Modulative property/Reflexive property

5) $x \cdot (x+2) = 0$ Distributive property/ $a^{b}\cdot a^{c} = a^{b+c}$

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Now we check the rational equation with each root:

x = 0

$\frac{x}{2} = \frac{x^{2}}{x-2}$

$\frac{0}{2} = \frac{0^{2}}{0-2}$

$0 = \frac{0}{-2}$

$0 = 0$

x = 0 is a solution of the rational equation.

x = -2

$\frac{x}{2} = \frac{x^{2}}{x-2}$

$\frac{-2}{2} = \frac{(-2)^{2}}{-2-2}$

$-1 = -1$

x = -2 is a solution of the rational equation.

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Papessa [141]

Answer:

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