All categories

3 years ago

Two curling stones collide on an ice rink. Stone 1 has a mass of 16 kg

Physics

1 answer:

nika2105 [10]3 years ago

4 0

Answer:

53.57 kg or 54 kg

-.81 m/s

Explanation:

m2= $\frac{v}{vf2} \\$ (2m1) -m1

v1f= $(\frac{m1-m2}{m1+m2})v$

You might be interested in

URGENT PLZ HELPPP!

Dovator [93]

λ = 3.125 m

λ = 2.83 m

<h3>Further explanation</h3>

Given

Frequency of radio : 96 MHz and 106 MHz

Required

The wavelength

Solution

Wavelength : from the crest to the crest of the next wave or the trough to the trough

Frequency (f): number of waves in one second

v = λ x f

λ = v : f

Input the value :

f = 96 MHz = 96 x 10⁶ Hz

λ = v : f

λ = 3 x 10⁸ : 96 x 10⁶

λ = 3.125 m

f = 106 MHz = 106 x 10⁶ Hz

λ = v : f

λ = 3 x 10⁸ : 106 x 10⁶

λ = 2.83 m

6 0

3 years ago

What is the car’s average velocity (in m/s) in interval between t=1.0s to t=1.5s?

Lemur [1.5K]

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, the formula for velocity is;

Velocity (in m/s) = distance/time

The distance the car covered in the completed question is divided by the difference in the time interval

The difference in the time interval will be = 1.5s - 1.0s = 0.5s

NOTE: the distance must be in meters or be converted to meters

7 0

3 years ago

Consider a system to be one train car moving toward another train car at rest. When the train cars collide, the two cars stick t

oee [108]

Answer:

Momentum after = 2400 kgm/s

Explanation:

Momentum after = momentum before

Momentum after = m1v1 +m2v2

Momentum after = (600)(4) + (400)(0)

Momentum after = 2400 kgm/s

3 0

3 years ago

Read 2 more answers

A sound wave enters a new medium where sound travels faster. How does this affect the frequency and wavelength of the sound?

Sophie [7]

The frequency stays the same and the wavelength increases.

Explanation;

Sound waves are a type of mechanical wave which requires a material medium for transmission. The transmission of such waves occurs as a result of vibration of particles in the material medium. The faster the vibration of the particles the higher the speed of the sound waves.

When a sound enters a new medium where the sound travels faster, it means the vibration of particles is high, and the wavelength of the waves increases which means the speed of the wave has increased. The frequency on the other hand will remain constant.

8 0

3 years ago

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi

Gnom [1K]

Answer:

(a) Acceleration of positron is 6.03 x 10¹³ m/s²

(b) Speed of positron after 8.70 x 10⁻⁹ s is 5.24 x 10⁵ m/s

Explanation:

Given :

Constant electric field, E = 343 N/C

Mass of positron, m = 9.1 x 10⁻³¹ kg

Charge of positron, q = +e = 1.6 x 10⁻¹⁹ C

(a) Coulomb force on the positron is determine by the relation :

F = q x E ....(1)

But, force is also equals to product of mass and acceleration. So,

F = ma .....(2)

Here a is acceleration.

From equation (1) and (2).

m x a = q x E

$a=\frac{qE}{m}$

Substitute the values of q, E and m in the above equation.

$a=\frac{1.6\times10^{-19}\times 343}{9.1\times10^{-31} }$

a = 6.03 x 10¹³ m/s²

(b) Initially, the positron is at rest, so its initial speed is zero.

The equation of motion for positron is :

v = u + at

Here v is final speed, u is initial speed and t is time.

Since, u is zero, so the equation becomes :

v = at

Substitute 8.70 x 10⁻⁹ s for t and 6.03 x 10¹³ m/s² for a in the above equation.

v = 6.03 x 10¹³ x 8.70 x 10⁻⁹ m/s

v = 5.24 x 10⁵ m/s

6 0

3 years ago