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Crank
3 years ago
8

Suppose students experiment with the tube and a variety of darts. Some darts have higher masses than others but are the same aer

odynamic shape. Assume air resistance is negligible for the darts. Should the students use a dart with large mass or small mass to launch the dart the farthest distance possible? State which dart will travel the farthest distance and explain your reasoning without manipulating equations.
Physics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

The dart with the small mass will travel the farthest distance.

Explanation:

Acceleration is proportional to force times mass, and inertia is proportional to mass. Inertia is the reluctance of a moving body to stop, and a stationary body to start moving (inertia increses with mass). Assuming they both have the same aerodynamic design, and that they are both launched with the same force applied for the same time duration, the dart with less small mass will accelerate faster than the big mass dart. From this we can see that the small dart will have covered a longer distance before the effect of the force stops, when compared to the more massive dart.

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A car is stopped at a traffic light. When the light turns green, the car starts from rest with an acceleration of 2.5 m/s2 . Als
erma4kov [3.2K]

Answer:

a) f = 453.3Hz

b) f = 443.1Hz

c) f = 420Hz

Explanation:

First of all we need to know the positions and velocities of both vehicles.

For the car:

Xc(-5) = 0m;   Vc(-5) = 0m/s

Xc(5) = 2.5*5^2/2=31.25m;  Vc(5)=2.5*5 = 12.5m/s

Xc(10)=2.5*10^2/2=125m;    Vc(10)=2.5*10=25m/s

For the truck:

Xt(-5)=10*(-5) = -50m;   Vt(5)=10m/s

Xt(5)=10*5 = 50m;       Vt(5)=10m/s

Xt(10)=10*10=100m;     Vt(10)=10m/s

Now for part a) t=-5s. The truck is behind the car, so:

f=\frac{C}{C-Vt}*fo = 453.3Hz

Now for part b) t=5s. The car is behind the truck, so:

f=\frac{C+Vc}{C+Vt}*fo = 443.1Hz

Now for part b) t=10s. The truck is behind the car, so:

f=\frac{C-Vc}{C-Vt}*fo = 420Hz

8 0
3 years ago
Describe what happens, at a microscopic level, when an object is charged by rubbing. For instance, what happens when a plastic p
olga_2 [115]

Answer:

Explanation:

The static charges are generated due to excess or deficiency of electrons, because these are the smallest quanta of charge available at the molecular level which can get transferred with minimal energy requirement.

These charges are usually generated by friction between  the two surfaces leading to the transfer of electron from one to another.

When a plastic pipe is rubbed with a cloth then due to friction the surface of the cloth loses electron which gets stuck at the surface of the pipe making it negatively charged.

7 0
4 years ago
If the force being applied to an object is doubled, what will happen to its<br> acceleration?
Minchanka [31]

Answer:

Acceleration decreases.

Explanation:

Hope this helps you.

4 0
3 years ago
If block D weighs 300 lb and block B weighs 275 lb determine the required weight of block C and the angle theta for equilibrium?
adoni [48]
Set up a free body diagram. 

<span>and by reason, Tcd = Tbd </span>

<span>Tbd y = 275 - 300*sinθ </span>
<span>Tcd y = Tc - 300*sin30 </span>

<span>Tbd x = 300*cosθ </span>
<span>Tcdx = 300 * cos30 </span>

<span>Tbd^2 = (275 - 300*sinθ)^2 + (300*cosθ)^2 </span>
<span>Tcd^2 = (300*sin30)^2 + (300 * cos30)^2 </span>

<span>(275 - 300*sinθ)^2 + (300*cosθ)^2 = (300*sin30)^2 + (300 * cos30)^2 </span>
<span>etc.</span>
5 0
3 years ago
A 5-kg object slides down a frictionless surface inclined at an angle of 30º from the horizontal. The total distance moved by th
erma4kov [3.2K]

Answer:

Workdone =0

Explanation:

The body is inclined at θ=30°,     s=10m,  m=5kg

Workdone by the object = FsCosθ

but the surface is a friction-less surface, this means coefficient of friction =0

F=μR

F=0*R

F=0

W=FScosθ

W=0*SCosθ

W=0

7 0
4 years ago
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