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Alex777 [14]
3 years ago
10

Potassium cyanide is a toxic substance, and the median lethal dose depends on the mass of the person or animal that ingests it.

The median lethal dose of KCN for a person weighing 215 lb (97.5 kg ) is 8.84×10−3 mol .
What volume of a 0.0250 M KCN solution contains 8.84×10−3 mol of KCN?

Express the volume to three significant figures and include the appropriate units.
Chemistry
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

0.354L

Explanation:

Given parameters:

Molarity of KCN  = 0.025M

Number of moles  = 8.84 x 10⁻³mol

Unknown:

Volume of KCN  = ?

Solution:

The molarity of a substance is expressed as;

       Molarity  = \frac{number of moles }{volume }  

 Volume of KCN   = \frac{number of moles }{molarity}

Now insert the parameters and solve;

  Volume of KCN  = \frac{0.00884}{0.025}   = 0.354L

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Answer:

= 100kJ

Explanation:

The reverse reaction's activation energy of a reaction is the activation energy of the forward reaction plus ΔH of the reaction:

Ea of forward reaction =75kJ

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<h3>Answer:</h3>

5.00 mol O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.<u> </u>

<u>Stoichiometry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.01 × 10²⁴ atoms O₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.01 \cdot 10^{24} \ atoms \ O_2(\frac{1 \ mol \ O_2}{6.022 \cdot 10^{23} \ atoms \ O_2})
  2. Multiply/Divide:                \displaystyle 4.99834 \ mol \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

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