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Genrish500 [490]
3 years ago
14

The molecule h2so4is ionized to h+ ions and so4- ions in water. would you predict this to result in a solution that is acidic or

basic?
Chemistry
1 answer:
8090 [49]3 years ago
3 0
Acidic. An increase in the amount of H+ ions indicates an acid solution.
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how will the following systems react when an increase in pressure occurs? note all species are gases N2O4<-->2NO2
frez [133]

 N2O4 ↔ 2NO2

The  following system  react as below  when  increase in pressure  occurs

The equilibrium   will  shift towards the left (more N2O4  is produced)

   <em><u>Explanation</u></em>

When  pressure increases  the equilibrium  shift toward  the side  of reaction with fewer  moles of gas.

 In the reaction  of N2O4 ↔  2 NO2  there  is only  1  moles   of N2O4  and 2 moles of NO2.

Therefore increase  in pressure led to shift of equilibrium towards the left. ( more N2O4 is produced)

7 0
3 years ago
Answer please i need it
bixtya [17]
I believe it’s c since it’s 2.5 cups of flour for each butter
8 0
2 years ago
The three-dimensional structure of macromolecules is formed and maintained primarily through noncovalent interactions. Which one
Nadusha1986 [10]

Answer:

Carbon-carbon bonds. (Ans.A).

Explanation:

None covalent bonds are different from covalent bonds, they are not formed by the sharing of electrons which is present between the bonded atoms. They are formed by the help of electrostatic attraction or some other type of interaction found between the ions or atoms.

A carbon-carbon bond is known as a covalent bond, and they are formed with the help of the sharing of electrons which is found between the two carbon atoms. Both carbon atoms have 4 electrons for bonding.

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Where does biomass comes from
tino4ka555 [31]
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7 0
3 years ago
A student does an experiment to determine the molar solubility of lead(II) bromide. She constructs a voltaic cell at 298 K consi
attashe74 [19]

Answer:

The molar solubility of lead bromide at 298K is 0.010 mol/L.

Explanation:

In order to solve this problem, we need to use the Nernst Equaiton:

E = E^{o} - \frac{0.0591}{n} log\frac{[ox]}{[red]}

E is the cell potential at a certain instant, E⁰ is the cell potential, n is the number of electrons involved in the redox reaction, [ox] is the concentration of the oxidated specie and [red] is the concentration of the reduced specie.

At equilibrium, E = 0, therefore:

E^{o}  = \frac{0.0591}{n} log \frac{[ox]}{[red]} \\\\log \frac{[ox]}{[red]} = \frac{nE^{o} }{0.0591} \\\\log[red] =  log[ox] -  \frac{nE^{o} }{0.0591}\\\\[red] = 10^{ log[ox] -  \frac{nE^{o} }{0.0591}} \\\\[red] = 10^{ log0.733 -  \frac{2x5.45x10^{-2}  }{0.0591}}\\\\

[red] = 0.010 M

The reduction will happen in the anode, therefore, the concentration of the reduced specie is equivalent to the molar solubility of lead bromide.

7 0
3 years ago
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