Answer:
The answer to your question is T2 = 319.4°K
Explanation:
Data
Volume 1 = V1 = 852 ml
Temperature 1 = T1 = 288°K
Volume 2 = V2 = 945 ml
Temperature 2 = T2 = ?
Process
To solve this problem, use Charles' law.
V1/T1 = V2/T2
-Solve for T2
T2 = V2T1/V1
-Substitution
T2 = (945 x 288) / 852
-Simplification
T2 = 272160 / 852
-Result
T2 = 319.4°K
<span>Li ----> Li+ + e-(oxidation)
now comes </span>
<span>Reduction: </span>
<span>H2 + 2e- ------> 2H
now by
</span>Multiplying (1) by 2 and adding in (2) will give you the required equation..
..
<span>2Li + H2 ---------> 2LiH
</span>half reaction are either oxidation or reduction
Answer:
glycerol-3-phosphate, ADP, H⁺
Explanation:
The reaction of converting glycerol to glycerol-3-phosphate which makes is unfavorable and is coupled with the second reaction which involves conversion of ATP to ADP which is high energetically favorable.
Reaction 1: Glycerol + HPO₄²⁻ ⇒ Glycerol-3-phosphate + water
Reaction 2: ATP + H₂O ⇒ ADP + HPO₄²⁻ + H⁺
The coupled reaction of both the reactions become favorable. Thus, the overall coupled reaction is:
<u>Glycerol + ATP ⇒ Glycerol-3-phosphate + ADP + H⁺</u>
The net products are = glycerol-3-phosphate, ADP, H⁺
