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3 years ago

Please help. asap. will mark brainliest

Mathematics

1 answer:

Dahasolnce [82]3 years ago

5 0

Answer:

option 1 and option 2 should be correct

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Find the values for a and b that would make the equality true.

zepelin [54]

Answer:

a = - 4, b = 5

Step-by-step explanation:

Expand the left side, then compare the coefficients of like terms.

- 3(2x² + ax + b)

= - 6x² - 3ax - 3b, compare to - 6x² + 12x - 15

Compare coefficients of x- terms

- 3a = 12 ( divide both sides by - 3 )

a = - 4

Compare constant terms

- 3b = - 15 ( divide both sides by - 3 )

b = 5

8 0

3 years ago

assume the the parent graph is y=x^2-2 write the equation of the parabola that would move it down 5 units

REY [17]

Answer:

Y= 1 (x^2-2)-5

Step-by-step explanation:

Use vertex form: y= a(x-h)+<u>k: k is what shifts the parbola up or down. Positive shifts it up while negative shifts it down.</u>

<u />

6 0

4 years ago

Amy's yearly salary is given by the equation y = 25,000 + 700x, where x is the number of years since 2007 and y is her salary in

marissa [1.9K]

Answer:

Amy's yearly salary in 2011 was $27,800

Step-by-step explanation:

we have

$y=25,000+700x$

where

x ---> is the number of years since 2007

y ---> Amy's yearly salary in dollars

To find out what was her salary in 2011, first determine the value of x

$x=2011-2007=4\ years$

substitute the value of x in the equation above

$y=25,000+700(4)$

$y=\$27,800$

therefore

Amy's yearly salary in 2011 was $27,800

3 0

4 years ago

Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180

torisob [31]

I got

$- \frac{6 3}{65}$

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

$\cos(a - b) = \cos(a) \cos(b) + \sin(a) \sin(b)$

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

${12}^{2} + {y}^{2} = {13}^{2}$

$144 + {y}^{2} = 169$

$25 = {y}^{2}$

$y = 5$

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

$( - 3) {}^{2} + {x}^{2} = {5}^{2}$

$9 + {x}^{2} = 25$

${x}^{2} = 16$

$x = 4$

so our opposite side is 4. sin =Opposite/Hypotenuse so our sin a =4/5.Sin is negative in the third quadrant so

sin a =-4/5.

Now use cosine difference formula

$- \frac{3}{5} \times \frac{5}{13} + - \frac {4}{5} \times \frac{12}{13}$

$- \frac{15}{65} + ( - \frac{48}{65} )$

$- \frac{63}{65}$

Hope this helps

6 0

3 years ago

What are the x-intercepts of y = 4x^2 + 4x + 1?

Slav-nsk [51]

Answer:

hope this helps:) have a good day

8 0

3 years ago

Read 2 more answers