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Annette [7]
3 years ago
6

If you ride quickly down a hill on a bicycle your eardrums are pushed in before they pop back. Why is this?

Physics
1 answer:
Kobotan [32]3 years ago
6 0

Answer:

This is due to variation bin air pressure at the two different altitudes, so air rushes out through the eustachian tube to hit the eardrum and back when u reach the ground

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Juan draws a free-body diagram of an object that is in dynamic equilibrium moving to the left. Which labels correctly complete t
Goryan [66]

Y is -45 N and X is 30.

When learning about forces, you have to understand that everything will cancel out on an object. So if the normal force is 45, to cancel it, the force of gravity has to be the negative of it. The same idea goes to frictional force. If the frictional force is -30 N, then to cancel it out, it has to be 30 N.

3 0
3 years ago
Read 2 more answers
1. Calculate how many electrons you need to get a charge of 1 coulomb.
belka [17]

1) To make a charge of 1 Coulomb, 6.25\cdot 10^{18} electrons are needed

2) 3.75\cdot 10^{19} electrons are needed to make that current

3) The potential difference is the work done per unit charge by an electric field

4) False, false, true

Explanation:

1)

The charge of one electron is equal to (in magnitude)

q=1.6\cdot 10^{-19}C

This is also known as fundamental charge, and it is also indicated with the letter e.

The charge in this problem is

Q=1 C

Therefore, in order to calculate how many electrons are in 1 Coulombd of charge, we just divide the total charge by the charge of one electron:

n=\frac{Q}{q}=\frac{1}{1.6\cdot 10^{-19}}=6.25\cdot 10^{18}

2)

The current intensity is defined as

I=\frac{Q}{t}

where

Q is the charge passing through a given point of a circuit in a time interval t

In this problem, we have

t = 60 s

I = 100 mA = 0.1 A

Therefore, the charge passing through the circuit is

Q=It=(0.1)(60)=6 C

We know that the charge of one electron is

q=1.6\cdot 10^{-19}C

So the number of electrons is

n=\frac{Q}{q}=\frac{6}{1.6\cdot 10^{-19}}=3.75\cdot 10^{19}

3)

The electrical voltage (also called potential difference) can be understood by using the concept of energy and work.

In fact, the work done by an electric field on a charge of magnitude q is

W=q\Delta V (1)

where \Delta V is the potential difference between the initial and final point of motion of the charge. The potential difference is responsible for "pushing" the charge through the circuit (in particular, a positive charge is pushed towards a point of lower potential, while a negative charge is pushed towards a point of higher potential), and when this happens, the electric potential energy of the charge (due to its position in the electric field) is converted into kinetic energy (energy of motion).

So, the potential difference is basically the work done per unit charge by an electric field responsible for the acceleration of a charge, as we can rewrite eq.(1) as

\Delta V = \frac{W}{q}

So in this case (where the electric voltage is 5 volts), it means that the work done by this electric field per unit charge is 5 J per Coulomb of charge.

4)

False: Current is the consequence and voltage is the cause. In fact, the voltage (the potential difference between two points in the circuit) is responsible for "pushing" the charges through the circuit, and when the charges start moving, they produce a current.

False: only the battery is a source of voltage. A battery is a device that produces an electromotive force (another name for potential difference), which is responsible for "pushing" the charges through the circuit. A socket, instead, is just a device used to connect another electric device to a voltage supply.

True: an electric current can only flow in a closed circuit. When the circuit is open, in fact, there is a point in the circuit where the flow of charge is interrupted: this means that the current can no longer flow in the circuit, so there is no electric current in an open circuit.

Learn more about current and potential difference:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

4 0
4 years ago
Suppose that an object is moving along a vertical line. Its vertical position is given by the equation L(t) = 2t3 + t2-5t + 1, w
Tatiana [17]

Answer:

The average velocity is

266\frac{m}{s},274\frac{m}{s} and 117\frac{m}{s} respectively.

Explanation:

Let's start writing the vertical position equation :

L(t)=2t^{3}+t^{2}-5t+1

Where distance is measured in meters and time in seconds.

The average velocity is equal to the position variation divided by the time variation.

V_{avg}=\frac{Displacement}{Time} = Δx / Δt = \frac{x2-x1}{t2-t1}

For the first time interval :

t1 = 5 s → t2 = 8 s

The time variation is :

t2-t1=8s-5s=3s

For the position variation we use the vertical position equation :

x2=L(8s)=2.(8)^{3}+8^{2}-5.8+1=1049m

x1=L(5s)=2.(5)^{3}+5^{2}-5.5+1=251m

Δx = x2 - x1 = 1049 m - 251 m = 798 m

The average velocity for this interval is

\frac{798m}{3s}=266\frac{m}{s}

For the second time interval :

t1 = 4 s → t2 = 9 s

x2=L(9s)=2.(9)^{3}+9^{2}-5.9+1=1495m

x1=L(4s)=2.(4)^{3}+4^{2}-5.4+1=125m

Δx = x2 - x1 = 1495 m - 125 m = 1370 m

And the time variation is t2 - t1 = 9 s - 4 s = 5 s

The average velocity for this interval is :

\frac{1370m}{5s}=274\frac{m}{s}

Finally for the third time interval :

t1 = 1 s → t2 = 7 s

The time variation is t2 - t1 = 7 s - 1 s = 6 s

Then

x2=L(7s)=2.(7)^{3}+7^{2}-5.7+1=701m

x1=L(1s)=2.(1)^{3}+1^{2}-5.1+1=-1m

The position variation is x2 - x1 = 701 m - (-1 m) = 702 m

The average velocity is

\frac{702m}{6s}=117\frac{m}{s}

5 0
3 years ago
Changing the length of an air column will alter its
AveGali [126]

Answer:

i think its pressure

Explanation:

7 0
4 years ago
Read 2 more answers
Diagram of an atom with labels
lina2011 [118]

See this. I hope you find your answer

6 0
3 years ago
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