Answer:
(d) 0.875 erlangs
Explanation:
In a digital network, the traffic intensity = 
where
a = average arrival rate of packets = 35 objects downloaded per second
L is the average packet length = 50,000 bits (e.g. in bits), and
R is the transmission rate = 2 Mbps = 2,000,000 bits per second
Traffic Intensity = 
Answer:
Option 1 and Option 3 are correct.
Explanation:
Linda is reading the promotion update through her google advertising profile while effectively installing transformation monitoring attributes to her site. She considers at least two with her advertisements have produced more than Hundred View-through transitions.
However, anyone viewing close until 30 seconds of such advertisements then anyone checking on such a portion of such advertising via View-through transformations.
Employers will regard you as a Valuable asset if you are able to adapt to changes, new ideas, and different work environments.
Answer:
- import java.util.ArrayList;
- public class Main {
-
- public static void main(String[] args) {
- ArrayList<String> strList =new ArrayList<String>();
- strList.add("to");
- strList.add("be");
- strList.add("or");
- strList.add("not");
- strList.add("to");
- strList.add("be");
- strList.add("hamlet");
-
- swapPairs(strList);
- System.out.println(strList);
- }
-
- public static void swapPairs(ArrayList<String> list){
- for(int i=0; i < list.size()-1; i+=2){
- String temp = list.get(i);
- list.set(i, list.get(i+1));
- list.set(i+1, temp);
- }
- }
- }
Explanation:
Firstly, let's create a method swapPairs that take one ArrayList (Line 18). In the method, use a for-loop to traverse through each item in the ArrayList and swap the items between the current items at index-i and at index-i+1 (Line 19-22). The index-i is incremented by two in next loop and therefore the next swapping will proceed with third and fourth items and so forth.
In the main program, create a sample ArrayList (Line 5-12) and then test the method (Line 14) and print the output (Line 15). We shall get [be, to, not, or, be, to, hamlet].
Answer:
A spanning tree is a subset of Graph G, which has all the vertices covered with minimum possible number of edges. Hence, a spanning tree does not have cycles and it cannot be disconnected.. By this definition, we can draw a conclusion that every connected and undirected Graph G has at least one spanning tree.
