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irga5000 [103]
3 years ago
11

The main difference between obsessive-compulsive personality disorder (OCPD) and obsessive-compulsive disorder (OCD) is that ___

_______.
people with OCPD know their disorder is irrational
people with OCD know their disorder is irrational
OCPD is an anxiety disorder consisting of disturbing thoughts
OCD is a mood disorder consisting of disturbing behaviors
Physics
2 answers:
maksim [4K]3 years ago
6 0

Answer:

B. people with OCD know their disorder is irrational

Explanation:

Got it right

Mrac [35]3 years ago
6 0

Answer:

B

Explanation:

Edge2021

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Calculate the electrical energy expended in a device across which the circuit voltage drops by 20.0 volts in moving a charge of
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Answer:

The answer is 80 Joules

Explanation:

Electrical energy = Q x V

Energy = 2 x 40

= 80

I just took the test and it was right :D

The correct answer is B.

I hope this helped! :D

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A neutron has a kinetic energy of 10 MeV. What size aperture would be necessary to observe diffraction effects?
Sedaia [141]

Answer: 9.33fm

Explanation:

Similarly as with a cut diffraction happens when part of the proliferating wave is cut off. This will occur for any object of request with a similar size as the wavelength of the diffracting wave.

Note, the object is moving at 14% of the speed of light. Be that as it may, the gamma factor is just 1% so taking care of the issue either relativistic or non relativistic conditions offers comparative responses.

Note: The size of the object has to be of the order of the wavelength of 10MeV. Therefore, size apperture that would be necessary to observe diffraction effect would be 9.33fm.

The calculations are in the attachment below:

8 0
3 years ago
A bullet of mass 20g is horizontally fired with a velocity of 150m/s from a pistol of mass 2 kg. What is the
kiruha [24]

Answer:

m1 = 20g (= 0.02 kg)

Mass of pistol, m2 = 2 kg

Initial velocity of the bullet (u1) and pistol (u2) = 0

Final velocity of the bullet, v1 = +150m s-1

Let v be the recoil velocity of the pistol.

Total momentum of the pistol and bullet after it is fired is

= (0.02 kg x 150 m s-1) + (2 kg x v m s-1)

= (3 + 2v) kg m s-1

Total momentum after the fire = Total momentum before the fire

3 + 2v = 0

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7 0
3 years ago
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