Answer:
CH3CHO+H2O → CH3OCH3 - addition
CH,CICH CI + Zn → C2H4 + ZnCl2 - elimination
CH3CH3Br + OH – CH3CH3OH + Br - substitution
2CH2COOH >>(CH3CO)20 + H20 - condensation
Explanation:
An addition reaction is a reaction in which a specie is added across the double bond as we can see in CH3CHO+H2O → CH3OCH3.
In an elimination reaction, a small molecule is lost from a saturated compound to form the corresponding unsaturated compound as in CH,CICH CI + Zn → C2H4 + ZnCl2
In a substitution reaction, a chemical moiety replaces another in a molecule as in; CH3CH3Br + OH – CH3CH3OH + Br .
A condensation reaction is in which two molecules are joined together to form a bigger molecule as in; 2CH2COOH >>(CH3CO)20 + H20.
Answer:
![m_{Co^{3+}}=0.563gCo^{3+}](https://tex.z-dn.net/?f=m_%7BCo%5E%7B3%2B%7D%7D%3D0.563gCo%5E%7B3%2B%7D)
Explanation:
Hello there!
In this case, since these mole-mass relationships are understood in terms of the moles of the atoms forming the considered compound, we first realize that the chemical formula of the cobalt (III) nitrate is Co(NO₃)₃ whereas there is a 1:1 mole ratio of the cobalt (III) ion (molar mass = 58.93 g/mol) to the entire compound. In such a way, we first compute the moles of the salt (molar mass = 58.93 g/mol) and then apply the aforementioned mole ratio to obtain the grams of the required cation:
![m_{Co^{3+}}=2.34gCo(NO_3)_3*\frac{1molCo(NO_3)_3}{244.95 gCo(NO_3)_3} *\frac{1molCo^{3+}}{1molCo(NO_3)_3} *\frac{58.93gCo^{3+}}{1molCo^{3+}} \\\\m_{Co^{3+}}=0.563gCo^{3+}](https://tex.z-dn.net/?f=m_%7BCo%5E%7B3%2B%7D%7D%3D2.34gCo%28NO_3%29_3%2A%5Cfrac%7B1molCo%28NO_3%29_3%7D%7B244.95%20gCo%28NO_3%29_3%7D%20%2A%5Cfrac%7B1molCo%5E%7B3%2B%7D%7D%7B1molCo%28NO_3%29_3%7D%20%2A%5Cfrac%7B58.93gCo%5E%7B3%2B%7D%7D%7B1molCo%5E%7B3%2B%7D%7D%20%5C%5C%5C%5Cm_%7BCo%5E%7B3%2B%7D%7D%3D0.563gCo%5E%7B3%2B%7D)
Best regards!
15.3 litres of water will be produced if we take 1.7 litres of Hydrogen
Explanation:
Let's take a look over synthesis reaction;
<u> </u>
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<u>Balancing the chemical reaction;</u>
<u> </u>
<u />
Thus, 2 moles of hydrogen molecules are required to form 2 moles of water molecules.
<u>Equating the molarity;</u>
<u />
= ![\frac{x*1}{2*18}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2A1%7D%7B2%2A18%7D)
(Since, the molecular mass of hyd and water is 2 and 18 respectively)
x=![\frac{1.7*2*18}{2*2}](https://tex.z-dn.net/?f=%5Cfrac%7B1.7%2A2%2A18%7D%7B2%2A2%7D)
x= 15.3 litres.
Thus,15.3 L of water will be produced if we take 1.7 litres of Hydrogen in a synthesis reaction.
Answer:
The dissociation constant of phenol from given information is
.
Explanation:
The measured pH of the solution = 5.153
![C_6H_5OH\rightarrow C_6H_5O^-+H^+](https://tex.z-dn.net/?f=C_6H_5OH%5Crightarrow%20C_6H_5O%5E-%2BH%5E%2B)
Initially c
At eq'm c-x x x
The expression of dissociation constant is given as:
![K_a=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OOH]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BC_6H_5O%5E-%5D%5BH%5E%2B%5D%7D%7B%5BC_6H_5OOH%5D%7D)
Concentration of phenoxide ions and hydrogen ions are equal to x.
![pH=-\log[x]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5Bx%5D)
![5.153=-\log[x]](https://tex.z-dn.net/?f=5.153%3D-%5Clog%5Bx%5D)
![x=7.03\times 10^{-6} M](https://tex.z-dn.net/?f=x%3D7.03%5Ctimes%2010%5E%7B-6%7D%20M)
![K_a=\frac{x\times x}{(c-x)}=\frac{x^2}{(c-x)}=\frac{(7.03\times 10^{-6} M)^2}{ 0.529 M-7.03\times 10^{-6} M}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7Bx%5Ctimes%20x%7D%7B%28c-x%29%7D%3D%5Cfrac%7Bx%5E2%7D%7B%28c-x%29%7D%3D%5Cfrac%7B%287.03%5Ctimes%2010%5E%7B-6%7D%20M%29%5E2%7D%7B%200.529%20M-7.03%5Ctimes%2010%5E%7B-6%7D%20M%7D)
![K_a=9.34\times 10^{-11}](https://tex.z-dn.net/?f=K_a%3D9.34%5Ctimes%2010%5E%7B-11%7D)
The dissociation constant of phenol from given information is
.
Answer:
A. 1 = 3 - 2
Explanation:
What defines an expression?
expression - An expression is a sentence with a minimum of two numbers and at least one math operation. This math operation can be addition, subtraction, multiplication, and division.
So if we look at the letter options we can see that A is the best choice.